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ASHA 777 [7]
2 years ago
14

Question 2 of 19

Chemistry
1 answer:
Alborosie2 years ago
3 0

Answer:

D

Explanation:

The temperature increases

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Property of a substance
Scrat [10]

There are many properties to substances.

I'll list some examples below:

  • Mass
  • Volume
  • Density
  • Conductivity
  • Malleability
  • Boiling point
  • Melting point
  • Heat capacity

Hope this helps! :3

8 0
2 years ago
What type of reaction does the following equation represent?
Ostrovityanka [42]

Answer:

B. double-replacement RXN

Explanation:

more specifically, this is a precipitation rxn.

6 0
2 years ago
Read 2 more answers
Explain why BH3 is trigonal planar and NH3 is trigonal pyramidal.
Troyanec [42]

Answer:o It is important to realise that mixing will be small unless there are electrons in the 4a1 LUMO, this is why NH3 is pyramidal while BH3 is planar! ... This mixing is very strong and stabilises the 3a1 MO substantially and hence NH3 is trigonal pyramidal and not planar.

Explanation:

3 0
3 years ago
c3H8 + 5O2 = 3CO2 + 4H2O When 44.0 grams of propane (C3H8) under goes complete combustion, how many grams of water will be produ
Umnica [9.8K]

<u>Answer:</u> 72 grams of water will be produced.

<u>Explanation:</u>

To calculate the number of moles, we use the formula:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}    ....(1)

Mass of propane = 44 grams

Molar mass of propane = 44 grams

Putting values in above equation, we get:

\text{moles of propane}=\frac{44g}{44g/mol}=1mole

For the reaction of combustion reaction of propane, the equation follows:

C_3H_8+5O_2\rightarrow 3CO_2+4H_2O

By Stoichiometry of the reaction,

1 mole of propane produces 4 moles of water.

So, 1 mole of propane will produce = \frac{1}{1}\times 4=4moles of water.

Now, to calculate the amount of water, we use equation 1, we get:

Molar mass of water = 18 g/mol

4mol=\frac{\text{Mass of water}}{18g/mol}

Mass of water produced = 72 grams

Hence,  72 grams of water will be produced.

6 0
3 years ago
The first-order decay of radon has a half-life of 3.823 days. How many grams of radon remain after 7.22 days if the sample initi
Nesterboy [21]

substitute: <span><span>t<span>1/2</span></span>=<span><span>ln(2)</span>k</span>→k=<span><span>ln(2)</span><span>t<span>1/2</span></span></span></span> Into the appropriate equation: <span>[A<span>]t</span>=[A<span>]0</span>∗<span>e<span>−kt</span></span></span> <span>[A<span>]t</span>=[A<span>]0</span>∗<span>e<span>−<span><span>ln(2)</span><span>t<span>1/2</span></span></span>t</span></span></span> <span>[A<span>]t</span>=(250.0 g)∗<span>e<span>−<span><span>ln(2)</span><span>3.823 days</span></span>(7.22 days)</span></span>=67.52 g</span>

6 0
3 years ago
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