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allochka39001 [22]
3 years ago
15

Which of the following are sources of revenue for media companies? A. Direct sales to producers B.advertising and subscriptions

C. Online purchase D. Capital investments
Chemistry
2 answers:
9966 [12]3 years ago
6 0
<h2>Answer:</h2>

The revenue source is <u>B. advertising and subscriptions</u>.

<h2>Explanation:</h2>

One of the most significant parts of media is the way that the media business is only that: an industry. Most media makers and outlets are business in nature, with the primary goal of profiting. There are a few strategies or “income models” that media organizations use to profit.

<u>The four most regular income models are: </u>

  • Advertising
  • Subscription
  • Pay-per term
  • Merchandising

Thus, from the options given in the question, option B which states that Advertisement and subscription is considered as best option for the given question.

Fed [463]3 years ago
5 0

Answer:

c

Explanation:

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During a synthesis reaction, 1.8 grams of magnesium reacted with 6.0 grams of oxygen. What is the maximum amount of magnesium ox
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<em>Mg + 1/2O₂ → MgO,</em>

1.0 mole of Mg reacts with 0.5 mole of oxygen to produce 1.0 mole of MgO.

  • We need to calculate the no. of moles of (1.8 g) of Mg and (6.0 g) of oxygen:

no. of moles of Mg = mass/molar mass = (1.8 g)/(24.3 g/mol) = 0.074 mol.

no. of moles of O₂ = mass/molar mass = (6.0 g)/(16.0 g/mol) = 0.375 mol.

<em>So. 0.074 mol of Mg reacts completely with (0.074/2 = 0.037 mol) of O₂ which be in excess.</em>

<em></em>

<em><u>Using cross multiplication:</u></em>

1.0 mole of Mg produce → 1.0 mol of MgO.

∴ 0.074 mol of Mg produce → 0.074 mol of MgO.

<em>∴ The amount of MgO produced = no. of moles x molar mass </em>= (0.074 mol)(40.3 g/mol) = <em>2.98 g.</em>

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