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Korvikt [17]
3 years ago
8

In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither

red nor green?
A. 8/21

B. 2/7

C. 1/3

D. 2/3
Mathematics
1 answer:
Mars2501 [29]3 years ago
8 0

Answer:

b 2/7

Step-by-step explanation:

Because there is a 6/21 chance and 2/7=6/21

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Answer:

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Step-by-step explanation:

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Answer:

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\rule[225]{225}{2}

Hope this helped!

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