M = hours driven by Maria
c = hours driven by Carlos
since we know that Carlos was driving at an average of 52 mph, then in 1 hour he drove 52 miles, in 2 hours he drove 2*52 miles in "c" hours he drove c*52 miles or
52c.
Maria on the other hand is faster and does 54 mph, in 1 hour she does 1 * 54 miles, and on 2 hours she does 2 * 54 miles and in "m" hours she does m * 54 miles or
54m.
now, we know the total amount of miles they both drove is 217, so whatever "m" and "c" are we know that
54m + 52c = 217.
we also know it took 4.1 for the whole trip, so
m + c = 4.1.

so Maria drove for 1.9 hours.
How many hours did Carlos drive for? well, c = 4.1 - m.
Answer:
1987.2
Step-by-step explanation:
We can write a proportion to find the total amount in the choir using the information given. A proportion is two equivalent ratios set equal to each other. Since we know the strength of students increased by 8% to 2160 then the original was 92%.

We will cross multiply the numerator of one ratio with denominator of the other. And then solve for y.
92(2160)=100(y)
198720=100y
y=1987.2
There are 1987.2 as the original strength of students.
C)-2/3is the answer because when your have 2/3+-2/3 will equal 0 in which justifies the additive inverse
Answer: 90/8=11.25
Step-by-step explanation:
Answer:
Range of the average number of tours is between 150 and 200 including 150 and 200.
Step-by-step explanation:
Given:
The profit function is modeled as:

The profit is at least $50,000.
So, as per question:

Now, rewriting the above inequality in terms of its factors, we get:

Now,
![x0\\x>200,(x-150)(x-200)>0\\For\ 150\leq x\leq200,(x-150)(x-200)\leq 0\\\therefore x=[150,200]](https://tex.z-dn.net/?f=x%3C150%2C%28x-150%29%28x-200%29%3E0%5C%5Cx%3E200%2C%28x-150%29%28x-200%29%3E0%5C%5CFor%5C%20150%5Cleq%20x%5Cleq200%2C%28x-150%29%28x-200%29%5Cleq%200%5C%5C%5Ctherefore%20x%3D%5B150%2C200%5D)
Therefore, the range of the average number of tours he must arrange per day to earn a monthly profit of at least $50,000 is between 150 and 200 including 150 and 200.