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erastova [34]
3 years ago
9

Consider the polynomial f(x)=2x^5-3x^4+x-6 (x )equals 2 x Superscript 5 Baseline minus 3 x Superscript 4 Baseline plus x minus 6

. Write the degree of this​ polynomial, its leading​ term, its leading​ coefficient, and its constant term.
Mathematics
1 answer:
melamori03 [73]3 years ago
3 0

Answer:

degree of polynomial = 5

leading term = 2x^{5}

leading coefficient = 2

constant term = -6

Step-by-step explanation:

f(x) = 2x^{5}-3x^{4}+x-6

(i) The degree of the polynomial = 5. That is, the highest power of x

(ii) Leading term = 2x^{5}. This is the term with the highest power of x.

(iii) Leading Coefficient = 2. That is, the coefficient of the leading term (2x^{5})

(iv) Constant term = -6. This is the term that is independent of x or the term in which x doesn't appear.

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2 years ago
Enter the solution (x, y) to the system of equations shown<br> x = 2.5<br> 5y + 2x = -10
Llana [10]

Answer:

x=2.5, y=-5. (2.5, -5).

Step-by-step explanation:

5y+2(2.5)=-10

5y+5=-10

5y=-10-5

5y=-15

y=-15/5

y=-5

7 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%5Cfrac%7B%283a%5E2b%29%5E3%7D%7B9%28ab%29%5E4%7D" id="TexFormula1" title="\frac{(3a^2b)^3}{9(
VladimirAG [237]

You first multiply the outside exponents into the numbers in the parentheses.

When you have an exponent being multiplied directly to another exponent, you multiply the exponents together.

For example(because I am a bad explainer):

(x^{2} )^4= x^{2(4)} = x^8

(x^4)^3 = x^{4(3)} = x^{12}


When you divide an exponent by an exponent, you subtract the exponents

For example:

\frac{x^4}{x^1} =x^{4-1}=x^3


When you have a negative exponent, you move it to the other side of the fraction to make the exponent positive

For example:

x^{-3}=\frac{1}{x^3}

\frac{1}{y^{-5}}=\frac{y^5}{1}=y^5



\frac{(3a^2b)^3}{9(ab)^4}

You can think of it like this if you want:

\frac{(3^1a^2b^1)^3}{9(a^1b^1)^4}  Now multiply the outside exponents into the exponents in the parentheses

\frac{3^3a^6b^3}{9(a^4b^4)} =\frac{27a^6b^3}{9(a^4b^4)} Divide 27 and 9

\frac{3a^6b^3}{a^4b^4} =(3)(a^{6-4})(b^{3-4})=(3)(a^2)(b^{-1})=(3)(a^2)(\frac{1}{b^1})=\frac{3a^2}{b}



Your answer is \frac{3a^2}{b}



5 0
3 years ago
Determine the area of a parallelogram if<br> its base is 16 cm and its height is 7 cm.
ella [17]
<h3>Answer: 112 square cm</h3>

=====================================

Work Shown:

area = base*height

area = 16*7

area = 112 square cm

----------------

Extra info (optional section):

The area formula for a parallelogram is the same as the formula for a rectangle. Imagine tilting a rectangle so that it's slanted. The area has not changed.

Or another thing to imagine is that let's say we had a stack of 2 by 4s. If the stack is perfectly vertical, aka forming a rectangle, then we can nudge the beams so that we can form a slanted parallelogram instead. Both configurations involve the same amount of wood, and therefore would lead to the same frontal surface area.

3 0
3 years ago
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