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Fofino [41]
4 years ago
5

If the second term of an arithmetic sequence is 5 and the fourth term is 12, what is the 37th term?

Mathematics
2 answers:
neonofarm [45]4 years ago
7 0
By using the information in the question, find a equation in the y=mx+b form. Then, plug in 37 as the x value and solve for y.
Setler [38]4 years ago
5 0
Aritmetic sequence
an=a1+d(n-1)
a1=first term
d=common differnce
an=nth term


given
a2=5
a4=12

so
a2=a1+d(2-1)=5
a4=a1+d(4-1)=12

a1+d=5
a1+3d=12
so 12-5=(a1+d)-(a1+3d)=2d=7
2d=7
divide by 2
d=3.5

a2=a1+3.5(1)
5=a1+3.5
minus 3.5 both sides
1.5=a1

an=1.5+3.5(n-1)
37th term
a37=1.5+3.5(37-1)
a37=1.5+3.5(36)
a37=1.5+126
a37=127.5


37th term is 127.5
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Step-by-step explanation:

A paired t-test is used to compare two population means where you have two samples in  which observations in one sample can be paired with observations in the other sample. For example  if we have Before-and-after observations (This problem) we can use it.  

Let put some notation  

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x: 57.8 35.7 54.5 56.8 51.1 70.8 77.3 51.6 54.7 63.6 59.2 59.2 55.8 38.5

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The system of hypothesis for this case are:

Null hypothesis: \mu_x- \mu_y \leq 0

Alternative hypothesis: \mu_x -\mu_y >0

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The third step would be calculate the standard deviation for the differences, and we got:

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t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=\frac{1.307 -0}{\frac{7.798}{\sqrt{14}}}=0.6271

The next step is calculate the degrees of freedom given by:

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