The sequence follows a minus 3 pattern: 12, 9, 6, 3, ....

Show with work please.

kolbaska11 [484]

Answer:

$\csc \left(\theta-\frac{\pi }{2}\right)=0.73$

Step-by-step explanation:

The identity you will use is:

$\csc \left(x\right)=\frac{1}{\sin \left(x\right)}$

So,

$\csc \left(\theta-\frac{\pi }{2}\right)$

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{\sin \left(-\frac{\pi }{2}+\theta\right)}$

Now, using the difference of sin

Note: state that $\text{sin}(\alpha\pm \beta)=\text{sin}(\alpha) \text{cos}(\beta) \pm \text{cos}(\alpha) \text{sin}(\beta)$

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{-\cos \left(\theta\right)\sin \left(\frac{\pi }{2}\right)+\cos \left(\frac{\pi }{2}\right)\sin \left(\theta\right)}$

Solving the difference of sin:

$-\cos \left(\theta\right)\sin \left(\frac{\pi }{2}\right)+\cos \left(\frac{\pi }{2}\right)\sin \left(\theta\right)$

$-\cos \left(\theta\right) \cdot 1+0\cdot \sin \left(\theta\right)$

$-\text{cos} \left(\theta\right)$

Then,

$\csc \left(\theta-\frac{\pi }{2}\right)=-\frac{1}{\cos \left(\theta\right)}$

Once

$\text{sec}(-\theta)=\text{sec}(\theta)$

And, $\text{sec}(\theta)=-0.73$

$-\frac{1}{\cos \left(\theta\right)}=-\text{sec}(\theta)$

$-\frac{1}{\cos \left(\theta\right)}=-(-0.73)$

$-\frac{1}{\cos \left(\theta\right)}=0.73$

Therefore,

$\csc \left(\theta-\frac{\pi }{2}\right)=0.73$

3 0

3 years ago

How many hundreds are all in the number of 44,813 ??

Iteru [2.4K]

Answer: Well, I thought about it and I was like, Well 813 right? Then I realized the question and was like: Nvm lol (Hope you find the answer!)

3 0

2 years ago

Refer to Expression 1 and Expression 2.

TiliK225 [7]

Expression 1 is 25

6*7-3^2*9+4^3

First simplify all the exponents to get 6*7 - 9 * 9 + 64 and then multiply the two numbers to get 42 - 81 + 64 and just add = 25

For expression 2, if you put the parantheses around (5+4)*2+6-2*2-1, it'll be 19

(5+4)*2+6-2*2-1

9*2+6-2*2-1

18+6-4-1

24-5

19

Remember order of operations

5 0

2 years ago

Which point is an x interception of the quadratic function f(x)=(x-8)(x+9)

viva [34]

$f(x)=(x-x_1)(x-x_2)\\\\(x_1,\ 0),\ (x_2,\ 0)-x\ interceptions$

$\text{We have}\ f(x)=(x-8)(x+9)=(x-8)(x-(-9))\\\\\text{therefore your answer is:}\\\\(8,\ 0),\ (-9,\ 0)$

6 0

3 years ago

Read 2 more answers

If a student is 65.0 in tall, what is her height in m? (2.54 cm = 1 inch)

spayn [35]

Answer:

Height of the student=1.651m

Step-by-step explanation:

Given: Height of a student= 65.0 inch.

To find: Height of a student in meters.

Solution:

We know that 1 inch=2.54 cm, then

65.0 inch will be = $2.54{\times}65.0$

65.0 inch will be= $165.2 cm$

Also, we know that 1cm= $\frac{1}{100} m$ , then

165.2 cm will be equal to= $\frac{1}{100}{\times}165.1$

165.2 cm will be equal to= $1.651 meters$

Therefore, the height of a student in meters will be 1.651 meters.

5 0

3 years ago