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3 years ago

Which of the following equations has both 1 and −3 as solutions?

2 answers:

7 0

X2+2x-3=0
factor
(x+3) (X-1)=O
set each factor to 0
x+3=0
x= -3

x-1=0
x=-1

therefore b is the correct answer

hope this helps

soldi70 [24.7K]3 years ago

5 0

The answer is B)

x2+2x−3=0

Factor left side of equation.

(x−1)(x+3)=0

Set factors equal to 0.

x−1=0 or x+3=0

x=1

or

x=−3

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How do you find the degree of an expression?

garri49 [273]

The degree of an expression in more than one variable is the highest sum of the powers of the variables in the terms.

Expression:

An algebraic expression is a combination of constant and variables connected by the signs of fundamental operations.

ex: 2x+5

Degree of an expression:

The degree of an expression in one variable is the highest exponent of the variable in that expression.

Ex:

2x^6 + x^4 + 5

Highest exponent = 6

so degree = 6

The degree of an expression in more than one variable is the highest sum of the powers of the variables.

Ex:

3x^1y^2 + 5x^3y^2 + 5

Sum of powers of variables = 3+2 = 5

Degree = 5.

Learn more about the expression here:

brainly.com/question/14083225

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4 0

1 year ago

Sam runs a lemonade stand. One day he collected $6.55 in nickels and dimes. The number of nickels was 6 more than half the numbe

vampirchik [111]

Answer:

Total number of dimes collected = 50

Step-by-step explanation:

Let the number of dimes collected = d

And the number of nickels collected = n

On day collection in nickels and dimes = $6.55

Since, 1 nickel = $0.05

Therefore, 'n' nickels = 0.05n

And 1 dimes = $0.10

Value of 'd' dimes = $0.10d

Total value of 'n' nickels and 'd' dimes = $(0.05n + 0.10d)

So the equation for the total value will be,

0.05n + 0.10d = 6.55

5n + 10d = 655 --------(1)

Number of nickels was 6 more than half the number of dimes.

n = $\frac{d}{2}$ + 6 ------(2)

By substituting the value 'n' from equation (2) to equation (1)

5( $\frac{d}{2}$ + 6) + 10d = 655

$\frac{5d}{2}$ + 30 + 10d = 655

$\frac{25d}{2}$ = 655 - 30

25d = 625 × 2

d = $\frac{1250}{25}$

d = 50

Therefore, total number of dimes collected = 50

6 0

3 years ago

If(x) = -2x and g(x) = 3 + x^2, what is the value of g(f(2))?

Ostrovityanka [42]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

the first term of a arithmetic sequence is 2 and the 4th term is 11, how do I find the sum of the first 50 terms

Rama09 [41]

$\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
a_1=2\\
a_4=11\\
n=4
\end{cases}
\\\\\\
a_4=2+(4-1)d\implies 11=2+(4-1)d\implies 11=2+3d
\\\\\\
9=3d\implies \cfrac{9}{3}=d\implies \boxed{3=d}\\\\
-------------------------------\\\\$

$\bf \textit{now, what's the 50th term anyway?}
\\\\\\
n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
a_1=2\\
n=50\\
d=3
\end{cases}
\\\\\\
a_{50}=2+(50-1)3\implies a_{50}=2+147\implies a_{50}=149\\\\
-------------------------------\\\\$

$\bf \textit{sum of a finite arithmetic sequence}\\\\
S_n=\cfrac{n}{2}(a_1+a_n)\quad 
\begin{cases}
n=50\\
a_1=2\\
a_{50}=149
\end{cases}\implies S_{50}=\cfrac{50}{2}(2+149)$

7 0

4 years ago

C=59(F−32)

mestny [16]

Answer: here u go ig

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers