Say you have the fraction 1/2 to the power of 2, so 1/2^2. You could also write this down as: 1/2*(times)1/2 or 0,5*0,5. Whenever you multiply by a number smaller than one, the outcome will get smaller. Whenever you multiply by a number larger than one, the outcome will be larger.
Answer:

Step-by-step explanation:
Given
5 tuples implies that:

implies that:

Required
How many 5-tuples of integers
are there such that
From the question, the order of the integers h, i, j, k and m does not matter. This implies that, we make use of combination to solve this problem.
Also considering that repetition is allowed: This implies that, a number can be repeated in more than 1 location
So, there are n + 4 items to make selection from
The selection becomes:



Expand the numerator




<u><em>Solved</em></u>
Answer:
35
Step-by-step explanation:
4 x 15 = 60
-4 x 5 = - 20
-1 x 5 = -5
60 - 20 - 5 = 35
<u>Given</u>:
Given that the data are represented by the box plot.
We need to determine the range and interquartile range.
<u>Range:</u>
The range of the data is the difference between the highest and the lowest value in the given set of data.
From the box plot, the highest value is 30 and the lowest value is 15.
Thus, the range of the data is given by
Range = Highest value - Lowest value
Range = 30 - 15 = 15
Thus, the range of the data is 15.
<u>Interquartile range:</u>
The interquartile range is the difference between the ends of the box in the box plot.
Thus, the interquartile range is given by
Interquartile range = 27 - 18 = 9
Thus, the interquartile range is 9.
Answer:
X= -1
Step-by-step explanation: