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2 years ago

What is t if 3/5=2/3t.

Mathematics

1 answer:

Dvinal [7]2 years ago

6 0

<span><span>т = <span><span>9/10

Я сподіваюсь допомогла ^ - ^
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Find the area of triangle ABC with vertices A(2,1), B (12,2), C (12,8). Hence, or otherwise find the perpendicular distance from

Lapatulllka [165]

<h2>The area of a triangle is =54 square units</h2><h2>The perpendicular distance from B to AC is = $\frac{108}{\sqrt{149} } units$ </h2>

Step-by-step explanation:

Given a triangle ABC with vertices A(2,1),B(12,2) and C(12,8)

$x_1=2,y_1=1,x_2=12,y_2=2,x_3=12 and y_3=8$

The area of a triangle is= $\frac{1}{2} [x_1(y_2-y_3) +x_2 (y_3- y_1)+x_3(y_1-y_2)]$

= $|\frac{1}{2} [2(2-8+12(8-1)+12(1-2)]|$

= $|-54|$ = 54 square units

The length of AC = $\sqrt{(x_1-x_3)^{2} +(y_1-y_3)^2}$

= $\sqrt{(2-12)^{2} +(1-8)^2}$

= $\sqrt{149}$ units

Let the perpendicular distance from B to AC be = x

According To Problem

$\frac{1}{2} \times x \times \sqrt{149} = 54$

⇔ $x =\frac{108}{\sqrt{149} }$ units

Therefore the perpendicular distance from B to AC is = $\frac{108}{\sqrt{149} } units$

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2 years ago

Can some figure this out

NeX [460]

Hello,

As 4²+(5/2)²=22.25=89/4 (Pytagorean theorem)
Perimeter of the triangle =2*√89 /2 +5 =5+√89
Lateral area: 18*(5+√89)
Total area= 90+18√89+ 4*5/2 *2 =110+18√89 ≈279.811..(ft²)

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3 years ago

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Step-by-step explanation:

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2 years ago

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3 years ago

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