What is t if 3/5=2/3t.

How do I graph -2=-2x+y

igor_vitrenko [27]

You must first set the y by itself. And use the slope formula to find the slope. 2 would be the point for the y axis

6 0

3 years ago

I need help is it A B C or D

nata0808 [166]

C because you have to think a bout how to get from y to x

3 0

3 years ago

Katherine and Shally had $288 altogether. Katherine gave 1/3 of her share to Shally and their father gave $68 to Shally. They no

erastova [34]

1/3 of $288 is $96 So, therefore Shally had $96 at first.
But They both didn't have the same amount of money after too because:
1/3 of $288 is $96
$96 + $68 = $164 So Shally has $164

Now, $288 - $96 = $192. So Katherine has $192

So therefore they did not have the same amount of money but 1/3 of $288 is $96

4 0

3 years ago

If a test of H subscript 0 colon space mu subscript D equals 0 space v s. space H subscript a colon space space mu subscript D g

lara [203]

Answer:

$p_v =P(t_{(n-1)}>t_{calculated}) =0.0601$

The p value on this case is given by the problem.

If we compare the p value with a significance level assumed $\alpha=0.05$ , we see that $p_v > \alpha$ and we can conclude that we FAIL to reject the null hypothesis that the difference mean between after and before is less or equal than 0.

Step-by-step explanation:

A paired t-test is used to compare two population means where you have two samples in which observations in one sample can be paired with observations in the other sample. For example if we have Before-and-after observations (This problem) we can use it.

Let put some notation

x=test value before , y = test value after

The system of hypothesis for this case are:

Null hypothesis: $\mu_y- \mu_x \leq 0$

Alternative hypothesis: $\mu_y -\mu_x >0$

The first step is calculate the difference $d_i=y_i-x_i$

The second step is calculate the mean difference

$\bar d= \frac{\sum_{i=1}^n d_i}{n}$

The third step would be calculate the standard deviation for the differences, and we got:

$s_d =\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1}$

The 4 step is calculate the statistic given by :

$t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=t_{calculated}$

The next step is calculate the degrees of freedom given by:

$df=n-1$

Now we can calculate the p value, since we have a right tailed test the p value is given by:

$p_v =P(t_{(n-1)}>t_{calculated}) =0.0601$

The p value on this case is given by the problem.

If we compare the p value with a significance level assumed $\alpha=0.05$ , we see that $p_v > \alpha$ and we can conclude that we FAIL to reject the null hypothesis that the difference mean between after and before is less or equal than 0.

4 0

3 years ago

Aren’t all of these answer chooses correct?

ivanzaharov [21]

Answer:

A beach in the next war with a friend of a friend of a

4 0

2 years ago