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4 years ago

Some help would be good

Mathematics

2 answers:

LekaFEV [45]4 years ago

8 0

$\frac{2x^{-4}}{3xy}=\frac{2}{3xy\cdot x^4}=\frac{2}{3x^5y}\\ \\ C.$

FinnZ [79.3K]4 years ago

8 0

C, because all negative exponents will end up as a denominator, just made positive. So in this instance, because you’re trying to make the x^-4 positive, you would slap that baby on the bottom to make it positive. And because there’s another X there, you add them together

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the relationship between altitude and the boiling point is linear.AT an altitude of 8300ft 8300 ft , the liquid

mojhsa [17]

Complete Question

The relationship between altitude and the boiling point is linear. At an altitude of 8300ft, the liquid boils at 194.23 ° F

At an altitude of 4200 ft , the liquid boils at 202.02° F.

Write an equation giving the boiling point b of the liquid, in terms of altitude a in feet . feet . What is the boiling point of the liquid at 2600ft

Answer:

The equation is $y = -0.001943x + 210.3569$

At 2600ft the temperature is $y = 205.3051 \ °F$

Step-by-step explanation:

From the question we are told that

The temperature at 8300ft is 194.23 ° F

The temperature at 4200 ft is 202.02° F

Generally the slope for this relationship is mathematically represented as

$m = \frac{ 202.2 - 194.23}{ 4200 - 8300}$

=> $m = 0.001943 ^o F / ft$

Generally the according to the point slope formula is

$y - y_1 = m(x -x_1 )$

=> $y - 194.23 = -0.001943 (x - 8300 )$

=> $y - 194.23 = -0.001943x + 16.1269$

=> $y = -0.001943x + 210.3569$

Now we are given from the question that x = 2600 ft

Then

$y = -0.001943(2600) + 210.3569$

=> $y = 205.3051 \ °F$

5 0

4 years ago

Find the equation of the sphere centered at (-9,9, -9) with radius 5. Normalize your equations so that the coefficient of x2 is

olganol [36]

<h2>Answer:</h2>

(a) x² + y² + z² + 18(x - y + z) + 218 = 0

(b) (x + 9)² + (y - 9)² + 56 = 0

<h2>Step-by-step explanation:</h2>

The general equation of a sphere of radius r and centered at C = (x₀, y₀, z₀) is given by;

(x - x₀)² + (y - y₀)² + (z - z₀)² = r² ------------------(i)

From the question:

The sphere is centered at C = (x₀, y₀, z₀) = (-9, 9, -9) and has a radius r = 5.

Therefore, to get the equation of the sphere, substitute these values into equation (i) as follows;

(x - (-9))² + (y - 9)² + (z - (-9))² = 5²

(x + 9)² + (y - 9)² + (z + 9)² = 25 ------------------(ii)

Open the brackets and have the following:

(x + 9)² + (y - 9)² + (z + 9)² = 25

(x² + 18x + 81) + (y² - 18y + 81) + (z² + 18z + 81) = 25

x² + 18x + 81 + y² - 18y + 81 + z² + 18z + 81 = 25

x² + y² + z² + 18(x - y + z) + 243 = 25

x² + y² + z² + 18(x - y + z) + 218 = 0 [equation has already been normalized since the coefficient of x² is 1]

Therefore, the equation of the sphere centered at (-9,9, -9) with radius 5 is:

x² + y² + z² + 18(x - y + z) + 218 = 0

(2) To get the equation when the sphere intersects a plane z = 0, we substitute z = 0 in equation (ii) as follows;

(x + 9)² + (y - 9)² + (0 + 9)² = 25

(x + 9)² + (y - 9)² + (9)² = 25

(x + 9)² + (y - 9)² + 81 = 25 [subtract 25 from both sides]

(x + 9)² + (y - 9)² + 81 - 25 = 25 - 25

(x + 9)² + (y - 9)² + 56 = 0

The equation is therefore, (x + 9)² + (y - 9)² + 56 = 0

6 0

4 years ago

1. In the given figure. BEST is a cyclic quadrilateral. ES is produced so that BE=SN. If ET is the bisector of angle BES, prove

padilas [110]

The triangle NET is an isosceles triangle as ET ≅ TN and ET = TN < EN given the condition that BEST is a cyclic quadrilateral.

<h3>How to determine the existence of an isosceles triangle</h3>

In this question we must apply geometric properties of angles and triangles to determine that the triangle NET is an isosceles triangle. Isosceles triangles are triangles with two sides of equal length. In addition, we must apply the geometric concept of proportionality.

Now we proceed to prove the existence of the isosceles triangle:

BE ≅ SN Given
ET is the bisector of ∠BES Given
ET/ES = ET/EB Definition of proportionality
ES = EB (3)
ES ≅ EB Definition of congruence
ET ≅ TN SSS Theorem/Result

Therefore, the triangle NET is an isosceles triangle as ET ≅ TN and ET = TN < EN given the condition that BEST is a cyclic quadrilateral. $\blacksquare$

To learn more on isosceles triangles, we kindly invite to check this verified question: brainly.com/question/2456591

7 0

3 years ago

Use the graph to find the solution.

DaniilM [7]

Answer:

W(2) = 5

Step-by-step explanation:

Because when you look at the graph, the y value is 5 when the x value is 2.

5 0

2 years ago

Read 2 more answers

The perimeter of a rectangle is 324 feet. the ration of the width to the length is 1:2. find the length and width of the rectang

hjlf

If the ratio of the width to the length is 1 : 2 then, we can represent their respective lengths using x and 2x.

Width = x
Length = 2x

2(x) + 2(2x) = 324
2x + 4x = 324
6x = 324
x = 54
2x = 108

The width is 54 ft. and the length is 108 feet. Hope this helps!

8 0

3 years ago