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Svetlanka [38]
4 years ago
5

Ocean currents influence all of the following except

Mathematics
2 answers:
Illusion [34]4 years ago
8 0
I'm sure it would be weather. :)
jonny [76]4 years ago
3 0
Radiation from the sun. That depends on the sun.
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John is cool leave him alone pls what did he ever do
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Which statements are correct about the average rate of change for the function f(x) = x2 + 9x + 18 ?
pshichka [43]

Answer:

Presumably this is a multiple choice question, and without seeing the potential answers, we can't tell you which ones are correct.

A few things can however be said about this function:

1) It describes a parabola that extends upward infinitely.  We can see this because it's in the classic format ax² + bx + c, and all terms are positive.

2) We can find the x-intercepts by solving for zero.  In this case we can do that by factoring it:

x² + 9x + 18 = 0

x² + 3x + 6x + 18 = 0

x(x + 3) + 6(x + 3) = 0

(x + 6)(x + 3) = 0

So the x intercepts occur at (-6, 0) and (-3, 0)

3) we can find its vertex by taking its derivative and solving for zero:

f'(x) = 2x + 9

0 = 2x + 9

x = -4.5

We can then plug that coordinate into the original function to find the y coordinate:

f(x) = x² + 9x + 18

f(-4.5) = 20.25 - 40.5 + 18

= -2.25

So the vertex is at (-4.5, -2.25)

4) As mentioned, the derivative of f(x) is f'(x) = 2x + 9.  The integral is:

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3 years ago
What is the area of the shaded part of the figure if =14
aniked [119]

The area of the shaded part is: 42.14 ft² .

<h3>Area of Square</h3>

Area = s²

<h3>Area of Quarter Circle </h3>

Area = 1/4πr²

Thus:

Area of the shaded part of the figure = area of square - area of quarter circle

Area of shaded part = s² - 1/4πr²

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r = 14 ft

Substitute

Area of shaded part = 14² - 1/4(3.14)(14²)

= 42.14 ft²

Therefore, the area of the shaded part is: 42.14 ft² .

Learn more about area of square on:

brainly.com/question/813881

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