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Contact [7]
3 years ago
15

The retail price of a suit is d dollars. Connor bought the suit with a 15% discount. Which expressions correctly represent the p

rice that Connor paid for the suit? Check all that are true.
0.85d
d - 0.15d
d - 15d
d + 0.15d
1.15d
Mathematics
2 answers:
natulia [17]3 years ago
5 0

Answer:

Expressions correctly represent the price that Connor paid for the suit are 0.85d  and d - 0.15d  .

Step-by-step explanation:

As given

The tax on the order is $1.571 and the final total for an order is $27.751 .

15% is written in the decimal form

= \frac{15}{100}

= 0.15

Thus

Discount price = 0.15 × Retail price of a suit

                        = 0.15 × d

                        = 0.15d

Thus

Price that Connor paid for the suit = Retail price of a suit - Discount price .

Put all the values in the above

                                                         = d - 0.15d

                                                         = 0.85d

Therefore the  expressions correctly represent the price that Connor paid for the suit are 0.85d  and d - 0.15d  .

dsp733 years ago
4 0
Both of the first two choices represent the amount Connor paid.

15% = 0.15, so when you subtract 15% of d from d, you get the 2nd expression. When you simplify that, you get the 1st expression.

The correct choices are ...
• 0.85d
• d - 0.15d
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In this question weight of a flea and an ant is given, but their units are different. So comparing and finding out the weight of flea and ant would be difficult. First thing that needs to be done is to bring the units of both the flea and the ant under same unit.
Weight of flea = 8 decigrams
Weight of ant = 3 milligrams.
Now let us convert the weight of the flea from decigrams to milligrams.
We already know that
1 decigram = 100 milligram
Then
8 decigrams = 100 * 8 milligrams
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The weight by which the flea is greater than the ant = (800 - 3) milligrams
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3 years ago
Read 2 more answers
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trapecia [35]

Answer:

4) d = 1

5) w = 11

6) q = 120

Step-by-step explanation:

<em>4)</em> 9d - 5 = 4

Adding 5 on both the sides ,

=  > 9d - 5 + 5 = 4 + 5

=  > 9d = 9

Dividing both the sides by 9 ,

=  >  \frac{9d}{9}  =  \frac{9}{9}

=  > d = 1

<em>5)</em> 6 - 3w =  - 27

Substracting 6 from both the sides ,

6  - 3w - 6 =  - 27 - 6

=  >  - 3w =  - 33

Dividing both the sides by -3 ,

=  >  \frac{ - 3w}{ - 3}  =  \frac{ - 33}{ - 3}

=  > w = 11

<em>6)</em> - 4 =  \frac{q}{8}  - 19

Adding 19 on both the sides ,

\frac{q}{8}  - 19 + 19 = - 4 + 19

=  >  \frac{q}{8}  = 15

Multiplying both the sides by 8 ,

=  >  \frac{q}{8}  \times 8 = 15 \times 8

=  > q = 120

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A binomial experiment must meet the following criteria:

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