<span>3-2(Cosx)^2 - 3Sinx = 0.
Recall (Sinx)^2 + (Cosx)^2 = 1.
Therefore (Cosx)^2 = 1 - (Sinx)^2
Substitute this into the question above.
</span><span>3-2(Cosx)^2 - 3Sinx = 0
3 - 2(1 - (Sinx)^2) - 3Sinx = 0 Expand
3 - 2 + 2(Sinx)^2 - </span><span><span>3Sinx = 0</span>
1 + 2(</span><span>Sinx)^2 - 3Sinx = 0 Rearrange
2(Sinx)^2 </span><span><span>- 3Sinx + </span>1 = 0
Let p = Sinx
2p^2 - 3p + 1 = 0 Factorise the quadratic expression
2p^2 - p - 2p +1 = 0
p(2p -1) - 1(2p -1) = 0
(2p-1)(p -1) = 0
Therefore 2p-1=0 or (p-1) = 0
2p=0+1 or (p-1) = 0
2p=1 or p = 0 +1.
p=1/2 or p = 1 Recall p = Sinx
Therefore Sinx = 1/2 or 1.
For 0<u><</u>x<u><</u>360
Sinx =1/2, x = Sin inverse (1/2) , x = 30,
(180-30)- 2nd Quadrant = 150 deg
Sinx = 1, x = Sin inverse (1) , x = 90
Therefore x = 30,90 & 150 degrees.
Cheers.</span>
Answer:
d. 3x - 1.
Step-by-step explanation:
45x^4−5x^2
The GCF is 5x^2 so we have:
5x^2(9x^2 - 1)
The expression in the parentheses is the difference of 2 squares so:
= 5x^2(3x - 1)(3x + 1)
If we let m₁, m₂, and m₃ be the measures of the angles of the triangle, the equation that would relate them to each other is,
m₁ + m₂ + m₃ = 180
Given the measures of the first two angles, the measure of the third angle is calculated through the equation,
m₃ = 180 - (m₁ + m₂)
Substituting the known expressions,
m₃ = 180 - (-3x⁵ + 2x²)
Simplifying,
<em> m₃ = 180 + 3x⁵ - 2x²</em>
The ostrich can run 20 miles in 40 minutes.
<u>Solution:</u>
Given that, An ostrich run 6 mile in 12 minutes
We have to find how far he could come in 40 minutes
Now, according to the given information
Ostrich runs 6 miles ⇒ 12 minutes
Then, “n” miles ⇒ 40 minutes
Now, by criss cross multiplication we get,
Hence, the ostrich can run 20 miles in 40 minutes
