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zzz [600]
3 years ago
15

You are outside on a clear night. You see the moon, but the face of the moon is all dark; no reflected light seen. This is most

likely a _________ moon.
Chemistry
2 answers:
lisov135 [29]3 years ago
5 0
New moon
btw your welcome :)
Dmitry [639]3 years ago
3 0
You are outside on a clear night. You see the moon, but the face of the moon is all dark; no reflected light seen. This is most likely a ''New'' moon.
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FIST ONE TO AWNSER GETS BRAINLYIST AND 50 POINTS IF CORRECT HURRY!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!1
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Answer:

B

Explanation:

Shows actual sacrifice in order to train and be the best.

7 0
3 years ago
Read 2 more answers
What is the concentration of Htions at a pH = 11?
Lostsunrise [7]
Answer:
a) 1 x 10^-11 mol/L
b) 1 x 10^-6 mol/L
c) 1 x 10^-5 fewer H+ ions

Explanation

pH stands for Power of Hydrogen, the more acidic a substance is, the more H+ ions it has rendering the substance acidic. a pH of 1 means the concentration of H+ ions is 1 x 10^-1. A pH of 7 means the concentration of H+ ions is 1 x 10^-7 and so on.

10^-11 has 10^-5 more H+ ions than 10^-6

Hope this helps :)
5 0
3 years ago
Question 8 Saved Which of the following energy transformations occurs when you eat a hamburger? Question 8 options: The chemical
Stels [109]
The first one is the answer.
6 0
3 years ago
Why do you elements in the same group have similar properties
lozanna [386]

Answer:

They have similar properties, because they share similar amounts of electrons in their outer shell, valence electrons! This means they will only be able to interact with other elements with those electrons so they often show similar properties.

Explanation:

7 0
3 years ago
Determine the mass of CaCO3 required to produce 40.0 mL CO2 at STP. Hint use molar volume of an ideal gas (22.4 L)
cupoosta [38]

Answer:

m_{CaCO_3}=0.179gCaCO_3

Explanation:

Hello,

In this case, since the undergoing chemical reaction is:

CaCO_3(s)\rightarrow CaO(s)+CO_2(g)

The corresponding moles of carbon dioxide occupying 40.0 mL (0.0400 L) are computed by using the ideal gas equation at 273.15 K and 1.00 atm (STP) as follows:

PV=nRT\\\\n=\frac{PV}{RT}=\frac{1.00 atm*0.0400L}{0.082\frac{atm*L}{mol*K}*273.15 K})=1.79x10^{-3} mol CO_2

Then, since the mole ratio between carbon dioxide and calcium carbonate is 1:1 and the molar mass of the reactant is 100 g/mol, the mass that yields such volume turns out:

m_{CaCO_3}=1.79x10^{-3}molCO_2*\frac{1molCaCO_3}{1molCO_2} *\frac{100g CaCO_3}{1molCaCO_3}\\ \\m_{CaCO_3}=0.179gCaCO_3

Regards.

3 0
3 years ago
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