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4 years ago

Is air an element, compound or mixture? explain your answer

Chemistry

2 answers:

vfiekz [6]4 years ago

7 0

Mixture cuz it contains gases, water vapor, dust and microbes

emmainna [20.7K]4 years ago

3 0

It is a mixture because the compounds that make up air e.g. oxygen (o2), Carbon dioxide (co2) and the most important Nitrogen which is an element and makes up 78.09% of air are not chemically bound in the way that compounds are because they can be separated easily and there has been no change in state to any of the compounds or elements in air!hope this helpful!

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Halogens have ------ electron affinity

4vir4ik [10]

They have a positive effinity

3 0

4 years ago

A 3.50 g sample of an unknown compound containing only C , H , and O combusts in an oxygen‑rich environment. When the products h

statuscvo [17]

Explanation:

First, calculate the moles of $CO_{2}$ using ideal gas equation as follows.

PV = nRT

or, n = $\frac{PV}{RT}$

= $\frac{1 atm \times 4.41 ml}{0.0821 Latm/mol K \times 293 K}$ (as 1 bar = 1 atm (approx))

= 0.183 mol

As, Density = $\frac{mass}{volume}$

Hence, mass of water will be as follows.

Density = $\frac{mass}{volume}$

0.998 g/ml = $\frac{mass}{3.26 ml}$

mass = 3.25 g

Similarly, calculate the moles of water as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

= $\frac{3.25 g}{18.02 g/mol}$

= 0.180 mol

Moles of hydrogen = $0.180 \times 2$ = 0.36 mol

Now, mass of carbon will be as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

0.183 mol = $\frac{mass}{12 g/mol}$

= 2.19 g

Therefore, mass of oxygen will be as follows.

Mass of O = mass of sample - (mass of C + mass of H)

= 3.50 g - (2.19 g + 0.36 g)

= 0.95 g

Therefore, moles of oxygen will be as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

= $\frac{0.95 g}{16 g/mol}$

= 0.059 mol

Now, diving number of moles of each element of the compound by smallest no. of moles as follows.

C H O

No. of moles: 0.183 0.36 0.059

On dividing: 3.1 6.1 1

Therefore, empirical formula of the given compound is $C_{3}H_{6}O$ .

Thus, we can conclude that empirical formula of the given compound is $C_{3}H_{6}O$ .

6 0

3 years ago

How many moles are in 68 grams of copper (ll) hydroxide, Cu(OH)2

Sveta_85 [38]

Molar mass Cu(OH)2 => 97.561 g/mol

Therefore:

1 mole Cu(OH)2 ------------ 97.561 g
? moles Cu(OH)2 ----------- 68 g

= 68 x 1 / 97.561

= 68 / 97.561

= 0.696 moles of Cu(OH)2

4 0

3 years ago

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Identify the type of friction acting in each scenario. A surfer rides an ocean wave. A bowling ball travels down a bowling lane.

pishuonlain [190]

1. fluid 2.rolling 3.air resistance 4.static

7 0

4 years ago

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Which of the following is an area targeted by countries to reduce environmental impact?

Ainat [17]

the answer is D on e2020