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slava [35]
3 years ago
14

There was a total of $548 collected for tickets to the school musical. The adult tickets cost $6 and the student tickets cost $4

. If 12 more student tickets were sold than adult tickets, then find the number of adult tickets sold.
Mathematics
1 answer:
Ivanshal [37]3 years ago
8 0

Answer:

1) 6A + 4S = 548

2) A +12 = S  multiplying by 4

2) 4A -4S = -48 then we add equation 1)

1) 6A + 4S = 548

10A = 500

50 Adult Tickets were sold and

62 Student Tickets were sold.

Double Check

50 * $6 = $300

62 * $4 = $248

Total = $548 Answer is correct!!!

Step-by-step explanation:

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mylen [45]

Hi there!

\large\boxed{\text{At (-1, -2), }\frac{dy}{dx} = -\frac{2}{5}}}

\large\boxed{\text{At (-1, 3), }\frac{dy}{dx} = -\frac{3}{5}}}

We can calculate dy/dx using implicit differentiation:

xy + y² = 6

Differentiate both sides. Remember to use the Product Rule for the "xy" term:

(1)y + x(dy/dx)  + 2y(dy/dx) = 0

Move y to the opposite side:

x(dy/dx) + 2y(dy/dx) = -y

Factor out dy/dx:

dy/dx(x + 2y) = -y

Divide both sides by x + 2y:

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3 years ago
What is the value of y in the parallelogram below?
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4 years ago
Karen claps her hand and hears the echo from a distant wall 0.113 s later. How far away is the wall? The speed of sound in air i
insens350 [35]

Answer:

19.3795 m

Step-by-step explanation:

If sound travels at 343 m/s and it took Karen 0.113 s to hear the echo from the wall, the distance travelled by the sound is:

D=343\frac{m}{s} *0.113\ s\\D= 38.759\ m

Note that the distance calculated above is the distance travelled from Karen to the wall and then back from the wall to Karen. Therefore, the distance between Karen and the wall is:

d=\frac{38.759}{2}\\d=19.3795\ m

The wall is 19.3795 m away from Karen.

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3 years ago
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