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2 years ago

BRAINLIEST !!! Can someone add me as a friend plz need to look someone up but cant till someone adds me

Mathematics

2 answers:

marishachu [46]2 years ago

8 0

Answer:

no hahahahahahahahahahahahahahahahahahahah

eimsori [14]2 years ago

4 0

Answer:

I have done what you want

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A six-sided number cube is rolled. Find the probability of rolling a 3 or a number greater than 4. A. 1/18 B. 1/6 C. 1/2 D. 2/3

ale4655 [162]

The answer is C.1/2 because there is only possible numbers are 3,5,6.

3 0

2 years ago

In 1859, 24 rabbits were released into the wild in Australia, where they had no natural predators. Their population grew exponen

Mashcka [7]

Answer:

a) P' = P

$P(t) = 24e^{0.693t}$ where t is step of 6 months

b) 7.7 years

c)1064.67 rabbits/year

Step-by-step explanation:

The differential equation describing the population growth is

$\frac{dP}{dt} = P$

Where t is the range of 6 months, or half of a year.

P(t) would have the form of

$P(t) = P_0e^{kt}$

where $P_0 = 24$ is the initial population

After 6 month (t = 1), the population is doubled to 48

$P(1) = 24e^k = 48$

$e^k = 2$

$k = ln(2) = 0.693$

Therefore $P(t) = 24e^{0.693t}$

where t is step of 6 months

b. We can solve for t to get how long it takes to get to a population of 1,000,000:

$24e^{0.693t} = 1000000$

$e^{0.693t} = 1000000 / 24 = 41667$

$0.693t = ln(41667) = 10.64$

$t = 10.64 / 0.693 = 15.35$

So it would take 15.35 * 0.5 = 7.7 years to reach 1000000

c. $P' = P_0ke^{kt}$

We need to resolve for k if t is in the range of 1 year. In half of a year (t = 0.5), the population is 48

$24e^{0.5k) = 48$

$0.5k = ln2 = 0.693$

$k = 1.386$

Therefore, $P' = 1.386*24e^{1.386t}$

At the mid of the 3rd year, where t = 2.5, we can calculate P'

$P' = 1.386*24e^{1.386*2.5} = 1064.67$ rabbits/year

4 0

2 years ago

39*10*100*1,000*0+37???? HELPPP

FromTheMoon [43]

Answer:

Step-by-step explanation:

Anything multiplied by 0 is 0 then you just add the 37

5 0

2 years ago

The plot below shows the graphs of three functions, f, g, and h, all of which determine the population of three different cities

monitta

So, here we have an exponential function.

Remember that an exponential function has the form:

$y=a(b)^x=a(1\pm\frac{r}{100})^x$

Where a represents an initial amount, and r is the rate of this amount to change. (Increase, or decrease).

So, given that the population of City A in 2000 was 40 thousand people and the population increased by 13% each year, we can say that

$\begin{gathered} a=40 \\ b=1+\frac{13}{100}=1.13 \end{gathered}$

So,

$f(x)=40(1.13)^x$

For city B:

$\begin{gathered} a=40 \\ b=1+\frac{16}{100}=1.16 \\ g(x)=40(1.16)^x \end{gathered}$

But something different happens with city C. This is not an exponential function, this is a linear function.

So,

$h(x)=40+10x$

7 0

4 months ago

F(x) = -2^2 +2 +13 Find f(9)

saveliy_v [14]

Answer:

jhvghvhgvvvvvvvvvvvvvvvvvvvv

Step-by-step explanation:

8 0

2 years ago