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Tamiku [17]
3 years ago
12

Alex and Ben shares £520 in the ratio 1:3. What fractions of the £520 does Ben receive?

Mathematics
1 answer:
Arisa [49]3 years ago
4 0
Ben would receive £390 while Alex would only receive £130
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The second option though i can not really see it.

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What is -1 7/8 + -2 1/4? Please explain why and a step by step :).
olya-2409 [2.1K]

9514 1404 393

Answer:

  -4 1/8

Step-by-step explanation:

Many people find it easier to factor out -1, then do the addition. The fractions need a common denominator before they can be added. A suitable denominator that is a multiple of both 4 and 8 is 8.

The fraction 1/4 = (1/4)(2/2) = (1·2)/(4·2) = 2/8.

__

So, the problem can be rewritten as ...

  -(1 7/8 +2 2/8)

  = -((1+2) +(7/8 +2/8))

  = -(3 +9/8)

The fraction 9/8 is an improper fraction equal to 8/8 +1/8 = 1 1/8. Then the sum is ...

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8 0
3 years ago
What is the midpoint of (10,6) and (4,9)
Leona [35]

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Please help me with algebra!<br> Don't answer if you don't know how to do it.
astra-53 [7]
This is all a bit complicated so try and stick with me on this one!

This one is the first problem in the first picture! a + 2 / a^2 + a - 1 / a + 1/ -a^2 - 2a - 1

= a^4 + a^3 - a^2 -  a / -a^5 - 3a^4 - 3a^3 - a^2

= -a^3 - a^2 + a + 1 / a^4 + 3a^3 + 3a^2 + a

= -a^3 - a^2 + a + 1/ a^4 + 3a^3 + 3a^2 + a

= (-a - 1) (a + 1) (a - 1) / a(a+ 1) (a + 1) (a + 1)

= -a + 1 / a^2 + a


The second problem in the first picture! 3x / y + 3x - y^2 / 3xy - 9x^2 + y^2 + 9x^2 / y^2 - 9x^2

= -81x^4y + 18x^2y^3 - y^5 / 243x^5 - 54x^3y^2 + 3xy^4


This one is for the last picture! 4y^2 + 4y + 1 / 4y - 8y^2 - 4y^2 + 1 / 4y + y 

= 16y^3 + 24y^2 / -32y^3 + 16u^2

= 16y + 24 / -32y + 16

= 2y + 3 / -4y + 2

I hope this was helpful!!!

Please remember to rate/thank/mark as brainliest if you see fit! (:



3 0
3 years ago
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