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ale4655 [162]
4 years ago
10

Name all sets of numbers to which this real number belongs 7.2 (repeating)=????????

Mathematics
1 answer:
kirza4 [7]4 years ago
7 0
Rationals, reals
........
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1096

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What is the sum of the first 7 terms of the geometric series:<br><br> -8 + (-4) + (-2) + 1 + 1/2+...
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a_1=-8;\ a_2=-4;\ r=a_2:a_1\to r=-4:(-8)=\dfrac{1}{2};\ n=7\\\\S_n=\dfrac{a_1(1-r^n)}{1-r}\\\\subtitute:\\\\S_7=\dfrac{-8\left[1-\left(\dfrac{1}{2}\right)^7\right]}{1-\dfrac{1}{2}}=\dfrac{-8\left(1-\dfrac{1}{128}\right)}{\dfrac{1}{2}}\\\\=\dfrac{-8\cdot\dfrac{127}{128}}{\dfrac{1}{2}}=-\dfrac{127}{16}\cdot\dfrac{2}{1}=-\dfrac{127}{8}=-15\dfrac{7}{8}
4 0
4 years ago
Dana buys dress shirts from a clothing manufacturer for s dollars each, and then sells the dress shirts in her retail clothing s
nydimaria [60]

Answer:

Consider the complete question is,

Dana buys dress shirts from a clothing manufacturer for s dollars each, and then sells the dress in her retail clothing store at a 35% markup

a. Write the markup as a decimal

b. write an expression for the retail price

c. What is the retail price of a dress shirt that Dana purchased for 32.00

d. How much was added to the original price of the dress shirt?

Reference : brainly.com/question/2202598

Solution :

Here, s represents the price of each dress shirt,

a. Since, markup percentage = 35%,

Thus, the markup in each shirt = 35% of price of each dress shirt

= 35% of s

=\frac{35s}{100}

= 0.35s

b. Retail price = original price + markup

= s + 0.35s

= 1.35s

c. if s = 32,

Retail price = 1.35(32) = 43.2

d. The added amount in original price = Retail price - original price

= 43.2 - 32

= 11.2

5 0
3 years ago
I need Help and I need it FAST!
alexandr1967 [171]

Answer:

<h2>\huge a)\frac{1}{ {3}^{9}. {6}^{18}  }</h2>

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • law of exponent
  • PEMDAS
<h3>tips and formulas:</h3>
  • {x}^{ - y}  <  =  >  \frac{1}{ {x}^{y} }
  • ( {x} ^{z} )^{y}  <  =  >  {x}^{y \times z}
<h3>let's solve:</h3>

( {3}^{3} . {6}^{6}  {)}^{  - 3}

\frac{1}{( {3}^{3}. {6}^{6} {)}^{3}   }

\frac{1}{ {3}^{3 \times 3}. {6}^{6 \times 3}  }

<h3>\frac{1}{ {3}^{9}. {6}^{18}  }</h3>
4 0
3 years ago
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