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Semenov [28]
2 years ago
11

A small combination lock on a suitcase has 4 ​wheels, each labeled with the 10 digits 0 to 9. how many 4 digit combinations are

possible if no digit is​ repeated? if digits can be​ repeated? if successive digits must be​ different?
Mathematics
1 answer:
tamaranim1 [39]2 years ago
8 0
This is the easiest way to solve this problem:

Imagine this represents how many combinations you can have for each of the 4 wheels (each blank spot for one wheel): __ __ __ __

For the first situation it says how many combos can we make if no digits are repeated.
We have 10 digits to use for the first wheel so put a 10 in the first slot 
10 __ __ __
Since no digit can be repeated we only have 9 options for the second slot
10 9_ __ __
Same for the third slot, so only 8 options
<u>10</u> <u> 9 </u> <u> 8 </u> __
4th can't be repeated so only 7 options left
<u>10</u> <u> 9 </u> <u> 8 </u> <u> 7 
</u><u>
</u>Multiply the four numbers together: 10*9*8*7 = 5040 combinations


For the next two do the same process as the one above.

If digits can be repeated? You have ten options for every wheel so it would look like this: <u>10</u> <u>10</u> <u>10</u> <u>10
</u>
10*10*10*10 = 10,000 combinations

If successive digits bust be different?
We have 10 for the first wheel, but second wheel only has 9 options because 2nd number can't be same as first. The third and fourth wheels also has 9 options for the same reason.

<u>10</u> <u> 9</u><u> </u> <u> 9 </u> <u> 9 </u>

10*9*9*9 = 7290 combinations






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sveta [45]

Answer:       A                 B

Group 1     0.25          0.75

Group 2    0.44          0.56

Step-by-step explanation:

Since we have given that

Number of people of A in group 1 = 15

Number of people of B in group 1 = 45

Total number of people in group 1 is given by

15+45=60

Relative frequency of people of A in Group 1 is given by

\frac{15}{60}=0.25

Relative frequency of people of B in Group 1 is given by

\frac{45}{60}=0.75

Similarly, Number of people of A in group 2 = 20

Number of people of B in group 2 = 25

Total number of people in group 2 is given by

20+25=45

Relative frequency of people of A in Group 2 is given by

\frac{20}{45}=0.44

Relative frequency of people of B in Group 2 is given by

\frac{25}{45}=0.56

Hence,        A                 B

Group 1     0.25          0.75

Group 2    0.44          0.56

6 0
3 years ago
What expression is equivalent to 10(2p+q)
boyakko [2]
There aren't any answer options so I will just simplify the expression:
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7 0
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which shows the students in order from greatest test score to lease test score Alex 0.95 Octavia 16/20 Tonya 9/10 Wilson 0.87 ​
Nonamiya [84]

Answer:

Alex (0.95), Tonya (0.90), Wilson (0.87), Octavia (0.80)

Step-by-step explanation:

To solve this, we have to convert all of the scores into either a decimal or a fraction. In this case, I will be solving all of them into decimals since it is easier.

Alex: 0.95

Octavia: 16/20 = 0.80

Tonya: 9/10 = 0.90

Wilson: 0.87

Therefore, we can order these from greatest score to least score.

Alex (0.95), Tonya (0.90), Wilson (0.87), Octavia (0.80)

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2 years ago
The slope of the line is -3. Use the coordinates of the labeled point to find the point-slope equation of the line.
nekit [7.7K]
m =  \dfrac{Y_2 - Y_1}{X_2-X_1}

-3 =  \dfrac{y + 7}{x - 5}

y + 7= -3(x - 5)

Answer A

8 0
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