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1 year ago

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3y=2x+15 Solve the equation for the y variable? Please help me out on this !!!

2 answers:

sp2606 [1]1 year ago

8 0

$\huge \boxed{\mathbb{QUESTION} \downarrow}$

3y=2x+15
Solve the equation for the y variable.

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

$3 y = 2 x + 15$

The equation is in standard form. So now, divide both sides by 3.

$\frac{3y}{3}=\frac{2x+15}{3} \\$

Dividing by 3 undoes the multiplication by 3.

$y=\frac{2x+15}{3} \\$

Divide 2x + 15 by 3.

$\huge \boxed{ \boxed{\bf \: y=\frac{2x}{3}+5 }}$

sukhopar [10]1 year ago

6 0

Step-by-step explanation:

$3y=2x+15 \:$

$y = \frac{2x + 15}{3}$

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2 years ago

Consider the equation y= -2x -3.

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2 years ago

Find the missing lengths: LK=15 and KH=9, find KI and HI.

Luda [366]

Answer:

KI=11.25 and HI=6.75

Step-by-step explanation:

Consider the below figure attached with this question.

According to Pythagoras Theorem:

$base^2+perpendicular^2=hypotenuse^2$

Use Pythagoras in triangle HKL

$LH^2+KH^2=LK^2$

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Taking square root on both sides.

$LH=12$

Let length of HI be x.

LI = 12+x

Use Pythagoras theorem in ΔKLI,

$(KI)^2+15^2=(12+x)^2$

$(KI)^2+225=x^2+24x+144$

$(KI)^2=x^2+24x+144-225$

$(KI)^2=x^2+24x-81...(1)$

Use Pythagoras theorem in ΔHKI,

$(KI)^2=x^2+9^2$

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From (1) and (2) we get

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Hence, the measure of HI is 6.75 units.

Substitute x=6.75 in equation (2).

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Taking square root on both sides.

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$KI=11.25$

Hence, the measure of KI is 11.25 units.

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2 years ago