For #1, I'd say it's "It will usually bond to multiple atoms which can provide a total of 4 additional electrons."
2. Ionic (I'm quite certain because anions/cations (-1 & +1) are Ionic from what I recall, if that's true it's Ionic.
3. "comparison of the associated families to which the elements belong" and
"the difference in electronegativities" are what I would choose, as I mentioned in a comment earlier.
If I'm wrong let me know, but I am at least 80% sure that these responses are correct from what I remember in Chemistry.
Answer is: Na₂SO₄ (sodium sulfate).
The solubility of sodium sulfate increases up to 32.38°C and than decreases at higher temperatures, the solubility becomes almost independent of temperature.
At 32.38°C it releases of crystal water and melting of the hydrated salt.
Sodium sulfate is the white, inorganic compound.
Sodium sulfate is highly soluble in water.
Explanation:
Helium is produced in radioactive process that occurs in deep and underground formations. They differ from other atmospheric gases. These radioactive decay of heavier nuclides that are unstable started about the time when the earth was formed.
- As they decay they give off lighter particles that can easily be broken down into more stable ones.
- One of the main product of the decay is alpha particles.
- They have the same atomic structure as helium
- These materials are trapped in underground formations.
Answer:
mix 1 mL of the stock solution of MgCl2, 300 mL of the stock solution of NaCl and 699 mL of water.
Explanation:
We need to determine the volume necessary of both stock solutions. When a dilution is made, a certain volume of the stock solution is collected and then more solvent is added to it until the volume is completed. So, the number of moles of the solute in both solutions are the same, and it is the concentration (C) multiplied by the volume (V). If 1 is the stock solution and 2 the diluted solution:
C1*V1 = C2*V2
So, in this case, the two solutions will be mixed, and then the volume will be completed with the solvent. So, for MgCl2:
C1 = 1.0 M
C2 = 1.0 mM = 0.001 M
V2 = 1.0 L = 1000 mL
1*V1 = 0.001*1000
V1 = 1 mL of the stock solution of MgCl2
For NaCl:
C1 = 0.50 M
C2 = 0.15 M
V2 = 1000 mL
0.50*V1 = 0.15*1000
V1 = 300 mL
So, it will be necessary 1 mL of the stock solution of MgCl2, 300 mL of the stock solution of NaCl and 699 mL of water.