The following equations are half reactions and reduction potentials. Ag+ (aq) + e– Ag(s) has a reduction potential of +0.80 V. C
2 answers:
Answer : The correct option is, (A) silver ion gains electrons more easily and is a stronger oxidizing agent than a chromium(III) ion.
Explanation :
The given half reaction are :
1st half reaction :
The reduction potential of this reaction = +0.80 V
2nd half reaction :
The reduction potential of this reaction = -0.74 V
From the reduction potentials, we conclude that the reaction which have positive reduction potential, they will gain electrons more easily and reduced itself and act as a stronger oxidizing agent.
Or we can say that the reaction which have negative reduction potential, they will lose electrons more easily and oxidized itself and act as a stronger reducing agent.
The reduction potential of 1st half reaction is positive and 2nd half reaction is negative.
Therefore, the silver ion gains electrons more easily and is a stronger oxidizing agent than a chromium(III) ion.
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Answer:
Ethane can be converted into 1- butanol in 4 different steps and reactions.
Explanation:
Step 1 : Ethane follows Markovnikov's rule and reacts with a protic acid called Hydrogen chloride to form Chloroethane.
Step 2: Chloroethane undergoes Wurtz reaction where it reacts with sodium metal in the presence of dry ether to form an higher alkane called butane.
Step 3: Butane undergoes chlorination where it reacts with an halogen called chlorine to form 1-chlorobutane.
Step 4: 1-chlorobutane reacts strong aqueous Potassium hydroxide (KOH) to form 1-butanol.
Attached to this answer is the handwritten conversion of Ethane to 1-butanol showing all the reagents and molecules synthesized along the way.
