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Naddik [55]
4 years ago
10

Calculate the concentration of oxalate ion (c2o42–) in a 0.175 m solution of oxalic acid (c2h2o4). [for oxalic acid, ka1 = 6.5 ×

10–2, ka2 = 6.1 × 10–5.]
Chemistry
1 answer:
Darina [25.2K]4 years ago
7 0

C2H2O4 C2HO4- + H+

0.175 - x x x + y

C2HO4- c2o42– + H+

x - y y x + y

K2 = (y) (x +y) / (x-y)

As, y << x

So, K2 = (y) (x) / (x)

K2 = y =6.1 × 10^–5

Hence, concentration of (c2o42–) 6.1 × 10^–5 M

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Equilibrium reaction of HA and KA follows the equation:

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According to Le-Chateliers principle, if there is any change in the variables of the reaction, the equilibrium will shift in the direction in order to minimize the effect.

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Equilibrium constant depends on the temperature of the system. It does not have any effect on any change of pH.

pH is defined as the negative logarithm of hydrogen ions present in the solution

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