Epsom salt is MgSO4.
We assume x water of hydration in the crystalline form.
Molecular mass of MgSO4 = 24+32+4*16=120
Molecular mass of MgSO4.xH2O = 120+18x
By proportion,
2.000/0.977 = (120+18x)/120
Cross multiply
0.977(120+18x) = 120*2.000
from which we solve for x
17.586x+117.24 = 240
x=122.78/17.586
=6.980
Answer: there are 7 water of hydration in Epsom salt, according to the experiment.
Note: more accurate (proper) results may be obtained by using exact values (3-4 significant figures) in the molecular masses. However, since water of hydration is the nearest integer, using approximate values (to at least two significant figures) suffice.
Answer:
D= 5 g/L
Explanation:
M= D x Vm
M is the molar mass = 112g/mol
D is the density
Vm is the molar volume whuch is 22.4L at STP
now substitute;
112 = D x 22.4
D= 112\22.4
D= 5 g/L
Answer:
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Explanation:
Hope this helps:)
Answer:
Add more substrate.
Explanation:
First let's explain why all the other options are wrong:
- The problem states that we <u>have optimum pH and optimum temperature</u>, this means that any change to those factors (increasing or decreasing) would slow down the reaction.
- <u>An inhibitor is called that way because its presence slows downs the reaction</u>, so more inhibitor would not speed up the reaction.
A <em>competitive inhibitor</em> is a substance that resembles the substrate that normally reacts with the enzime, so it binds to the enzime's active sites and prevents the substrate from doing so. Adding more substrate makes it more likely than a substrate molecule binds to an enzime's active site instead of the inhibitor ("it will outcompete the inhibitor and increase the reaction rate").
The number of protons
for all atoms of mercury will remain the same while different isotopes may have different number of neutrons.
Explanation:
Atoms should have equal numbers of protons and electrons. In our example, an atom of thirty six|chemical element, it should contain thirty six electrons since it contains 36 protons. Electrons are organized around atoms in a very special method.
