A has fixed one time fee of $12 and if you go to it say "m" months you pay $28 for each month, so your total cost at A is really 12 + 28m.
B has a fixed one time fee of $20 and if you go to it "m" months you pay $26 for each month, so you total cost at B is 20 + 26m.
how many months for the cost to be the same?
well, since the cost for both is the same, we can just get A's, knowing that B is the same
The answer is y=mx+b y=(-2)-(1/2)
Answer:
15.81
Step-by-step explanation:
Use the distance formula:
So the distance formula for two given points is
Distance= sqrt((x2-x1)^2 +(y2-y1)^2 ) =sqrt((-3-6)^2 +(-8-5)^2 )
=sqrt((-9)^2 +(-13)^2 )
=sqrt(81+169)
=sqrt(250)
=15.81
Hope this helped
:)
9.25 hope I have a nice day and stuff I have to write 20 words so
Answer:
y=400*x-500
Step-by-step explanation:
The expression that represents the problem is:
y=400*x-500
Function y represents earnings for one day.
400 is the fixed number that is charge for one hour work
x represents the number of hours that the technician has worked for one day
To find the total earnings you should multiply the fixed charge for one hour work (400) by the number of hours worked in a day.
Then you need to substract the cost of gasoline in a day, it is 500 and it is a constant in the equation since it doesn't depend on the number of hours worked.
So, the function is:
y=400*x-500
