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2 years ago

The incorrect work of a student to solve an equation 2(y + 6) = 4y is shown below.

Mathematics

1 answer:

Lina20 [59]2 years ago

4 0

Answer:

<h3>⇒ A. 2 should be distributed as 2y + 12, y = 6</h3>

Step-by-step explanation:

Here are the steps to solve this equation:

<u>Given:</u>

First step: 2(y+6)-4y

Use the distributive property.

<u>Distributive property:</u>

2(y+6)

2*y=2y

2*6=12

2y+12

Isolate the term of y from one side of the equations.

2y+12=4y

Subtract by 12 from both sides.

2y+12-12=4y-12

Solve.

2y=4y-12

Then, you subtract by 4y from both sides.

2y-4y=4y-12-4y

Solve.

2y-4y=-2y

-2y=-12

Divide by -2 from both sides.

$\sf{\dfrac{-2y}{-2}=\dfrac{-12}{-2}}$

Solve.

Divide the numbers from left to right.

<u>Solutions:</u>

-12/-2=6

$\Longrightarrow: \boxed{\sf{y=6}}$

<u>Therefore, the correct answer is A. "2 should be distributed as 2y+12, y=6".</u>

I hope this helps. Let me know if you have any questions.

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3 years ago

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Harlamova29_29 [7]

Answer:

x>\frac{53}{6}

Step-by-step explanation:

12x>140−34

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2 years ago

a volley ball player servers the ball. The ball follows a path given by the equation y=-0.01x^2+0.5x+3 where x and y are measure

dolphi86 [110]

Answer:

(a)

Distance from player should be 13.82 feet or 36.2 feet

(b)

The ball will go over the net

Step-by-step explanation:

we are given

The ball follows a path given by the equation

$y=-0.01x^2+0.5x+3$

where

x and y are measured in feet and the origin is on the court directly below where the player hits the ball

(a)

net height is 8 ft

so, we can set y=8

and then we can solve for x

$8=-0.01x^2+0.5x+3$

$8\cdot \:100=-0.01x^2\cdot \:100+0.5x\cdot \:100+3\cdot \:100$

$800=-x^2+50x+300$

$-x^2+50x-500=0$

$x^2-50x+500=0$

we can use quadratic formula

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{-50\pm \sqrt{50^2-4\left(-1\right)\left(-500\right)}}{2\left(-1\right)}$

$x=5\left(5-\sqrt{5}\right),\:x=5\left(5+\sqrt{5}\right)$

$x=13.82,x=36.2$

So, distance from player should be 13.82 feet or 36.2 feet

(b)

we can plug x=30 and check whether y=8 ft

$y=-0.01(30)^2+0.5(30)+3$

$y=9ft$

we know that

height of net is 8 ft

so, the ball will go over the net

5 0

3 years ago

Find the length of the third side. If necessary, write in simplest radical form.

Mazyrski [523]

Answer:

$\boxed {\boxed {\sf 8}}$

Step-by-step explanation:

This triangle has a small square, which represents a right angle. Therefore, we can use the Pythagorean Theorem.

$a^2+b^2=c^2$

Where <em>a</em> and <em>b </em> are the legs of the triangle and <em>c</em> is the hypotenuse.

In this triangle, 7 and √15 are the legs, because these sides make up the right angle. The unknown side is the hypotenuse, because it is opposite the right angle. So, we know two values:

$a= 7 \\b= \sqrt{15}$

Substitute these values into the formula.

$(7)^2+(\sqrt{15})^2=c^2$

Solve the exponents.

(7)²= 7*7=49

$49+ (\sqrt{15})^2=c^2$

(√15)²=√15*√15=15

$49+15=c^2$

Add.

$64=c^2$

Since we are solving for c, we must isolate the variable. It is being squared and the inverse of a square is the square root. Take the square root of both sides.

$\sqrt{64}=\sqrt{c^2} \\\sqrt{64}= c\\8=c$