X^2+y^2 = 16
can be written as
(x-0)^2+(y-0)^2 = 4^2
We see that the second equation is in the form
(x-h)^2 + (y-k)^2 = r^2
where
(h,k) = (0,0) is the center
r = 4 is the radius
The polar form of the equation is simply r = 4. Why is this? Because the radius is fixed to be 4 no matter what happens with theta. As theta goes from 0 to 360, the points generated all form a circle centered at (0,0) with radius 4.
Answer: r = 4
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Step-by-step explanation: Idk how to explain I’m just smart so I can figure it out
Answer:
the people would save 12 meters
Step-by-step explanation:
If it is a right triangle that has 45,45,90 angles, Than two side lengths would be the same, so there are two 30 meter side lengths. The path is 48 meters long, and the road would be 60 meters long (30+30), so you subtract 48 from 60, and get 12. You would save 12 meters
Solution:
X^2+11x+30
=X^2+(6+5)x+30
=X^2+6x+5x+30
=X(x+6)+5(x+6)
=(X+6)(x+5).
So,the answer is (x+6)(x+5).
<span>We already know that angles ECS and TRS are congruent, because they are both right angles (given). We also know that angles CSE and RST are congruent because they are vertical angles and vertical angles are always congruent. That gives us two sets of congruent angles. We just need to know something about one pair of sides to prove the two triangles congruent to each other. I do question the order of the letters in the names of the triangles--if that's really the order the letters are written in the problem, then we would need to know that ES is congruent to RT or that CS is congruent to ST. If the order of the letters of the names of the triangles is a little different we would need to know that CS is congruent to RS or that any of the other sides that appear to match are actually congruent. </span>
