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2 years ago

What is the answer to 7y + 5 + (3 - y)?

Mathematics

2 answers:

Pachacha [2.7K]2 years ago

6 0

Answer:

6y +8

Step-by-step explanation:

in order to solve this, take note of the bracket and combine the like terms.

solution

7y + 5 + (3 - y)

7y + 5 +3 -y

7y-y + 5+3

6y +8

Nataliya [291]2 years ago

4 0

Answer with factoring: 2(3y+4)

Answer with simplifying: 6y+8

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What are the solutions of this quadratic equation? x2 + 10 = 0 A. B. C. D.

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Answer:

x2+10=0A.B.C.D.

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2 years ago

What is an equation of the line that passes through the points (-6, -2) and

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Answer:

The equation of line is: $\mathbf{4x-3y=-18}$

Step-by-step explanation:

We need to find an equation of the line that passes through the points (-6, -2) and (-3, 2)?

The equation of line in slope-intercept form is: $y=mx+b$

where m is slope and b is y-intercept.

We need to find slope and y-intercept.

Finding Slope

Slope can be found using formula: $Slope=\frac{y_2-y_1}{x_2-x_1}$

We have $x_1=-6,y_1=-2, x_2=-3, y_2=2$

Putting values and finding slope

$Slope=\frac{2-(-2)}{-3-(-6)}\\Slope=\frac{2+2}{-3+6} \\Slope=\frac{4}{3}$

So, we get slope: $m=\frac{4}{3}$

Finding y-intercept

Using point (-6,-2) and slope $m=\frac{4}{3}$ we can find y-intercept

$y=mx+b\\-2=\frac{4}{3}(-6)+b\\-2=4(-2)+b\\-2=-8+b\\b=-2+8\\b=6$

So, we get y-intercept b= 6

Equation of required line

The equation of required line having slope $m=\frac{4}{3}$ and y-intercept b = 6 is

$y=mx+b\\y=\frac{4}{3}x+6$

Now transforming in fully reduced form:

$y=\frac{4x+6*3}{3} \\y=\frac{4x+18}{3} \\3y=4x+18\\4x-3y=-18$

So, the equation of line is: $\mathbf{4x-3y=-18}$

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2 years ago

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Answer:

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Step-by-step explanation:

(x − 6)(x + 0.7) = 0

using the zero product property

x-6=0 x+.7 =0

x-6+6 = 0+6 x+.7 -.7 = 0-.7

x = 6 x= -.7

sum of the solutions

6+-.7 = 5.3

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