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Hitman42 [59]
3 years ago
9

How do I solve #39???

Mathematics
1 answer:
olganol [36]3 years ago
8 0
Subtract exponents, divide coefficients

39/13t^7u^-6v-2
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What is the answer to this question?
katen-ka-za [31]

Answer:

10 in., 18.5 in., 31.5 in.

Step-by-step explanation:

Ask me if you need step-by-step, since the problem seems to be multiple choice.

8 0
3 years ago
What is the y-intercept -x 3y=9?
dedylja [7]
(0, 3)

<span>-x + 3y=9
to figure out the y-intercept, you must put the equation into y-intercept form first: y = mx + b

</span><span>-x+3y=9
3y = x + 9
y = (x/3) + (9/3)
y = x/3 + 3 
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2 years ago
Pls help will give brainliest
Shtirlitz [24]

Answer:

C, C, C

Hope This Helps!    Have A Nice Day!!

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3 years ago
Find the value.plzzz I will mark as the brillianest plzzzzzzzzzzzzzzzzzzzz​
Aleks [24]

Answer:

n= 75

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other n across from p= 105

Step-by-step explanation:

n and y are the same since the triangle is isoseles.

p is supplemetary to n

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7 0
3 years ago
Find the exact value of the given expression.<br> sin(2cos^-1(5/13))
xeze [42]

Answer:

+120/169 or -120/169

Step-by-step explanation:

  • let cos^{-1}[\frac{5}{13}  ] = \alpha

where, alpha is some angle that satisfies the assumed condition.

  • so, cos\alpha= 5/13

[ taking cos to the other side  or applying cos on both sides]

  • now, substitute this in the given expression
  • sin(2cos^-1(5/13)) = sin(2\alpha )

as sin\beta =  + or -\sqrt{1-(cos\beta) ^{2}

[by general trigonometry formula: cos^{2}[\beta]  +sin^{2}[\beta]=1]

so if  cos\alpha= 5/13, we can get sin\alpha from the above formula as + or - 12/13

(because, after taking square root on both sides we keep + or -]

  • as, sin2\beta  = 2*sin[\beta ]*cos[\beta ]

[by general trigonometry formula]

  • here, now sin[2\alpha ]=2*(+or- 12/13)*5/13\\

so, the final value can be 120/169 or -120/169.

4 0
3 years ago
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