Answer:
Mean : ![\mu = 195](https://tex.z-dn.net/?f=%5Cmu%20%3D%20195)
![\sigma = 8.3 cm](https://tex.z-dn.net/?f=%5Csigma%20%3D%208.3%20cm)
a) Find the probability that an individual distance is greater than 204.30 cm.
We are supposed to find P(Z>204.30)
x = 204.30
Formula : ![z=\frac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=z%3D%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D)
Substitute the value sin the formula :
![z=\frac{204.40-195}{8.3}](https://tex.z-dn.net/?f=z%3D%5Cfrac%7B204.40-195%7D%7B8.3%7D)
![z=1.13253](https://tex.z-dn.net/?f=z%3D1.13253)
P(Z>204.30)=1-P(Z<204.30)
Refer the z table
P(Z>1.13253)=1-P(Z<1.13253)
P(Z>1.13253)=1-0.8708
P(Z>1.13253)=0.1292
The probability that an individual distance is greater than 204.30 cm is 0.1292.
b) Find the probability that the mean for 20 randomly selected distances is greater than 192.80 cm
We are supposed to find P(Z>192.80)
x = 192.80
Formula : ![z=\frac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=z%3D%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D)
Substitute the value sin the formula :
![z=\frac{ 192.80-195}{8.3}](https://tex.z-dn.net/?f=z%3D%5Cfrac%7B%20192.80-195%7D%7B8.3%7D)
![z=-0.265](https://tex.z-dn.net/?f=z%3D-0.265)
P(Z>192.80)=1-P(Z<192.80)
Refer the z table
P(Z>-0.265)=1-P(Z<-0.265)
P(Z>-0.265)=1-0.3974
P(Z>-0.265)=0.6026
The probability that the mean for 20 randomly selected distances is greater than 192.80 cm is 0.6026
c) Why can the normal distribution be used in part (b), even though the sample size does not exceed 30
The normal distribution is used because the original population has normal distribution.
Divide total price by amount bought:
120.96 / 144 = 0.84
It cost $0.84 for 1 square foot.
It's 216 because you would just do the equation from left to right since pemdas doesn't really effect the order here
Step-by-step explanation:
the answer would be -9.
28x -63 = -315
add 63 to -63 and -315
there u get this
28x= -252
then divide 28 both sides
x=-9
A 6’9 you add up the heights in inches
6’1 = 73 inches
6’2 = 74 inches
6’3 = 75 inches
6’5 = 77 inches
6’9 = 81 inches
Add them together you get 380 then divide 380 by 5 (one for every height) you get 76 and 76 inches is equal to 6’4