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alexandr1967 [171]
3 years ago
5

Need help ASAP. Will give brainliest!!!!

Mathematics
1 answer:
julia-pushkina [17]3 years ago
8 0

B1 to H1, B3 to H2, B2 to H3.

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I need help I'm confused
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<h3><em>11) x+61 +  x+51 + 80 = 180 ( angle sum property )</em></h3><h3><em>2x + 192 = 180 </em></h3><h3><em>2x = 180 - 192 </em></h3><h3><em>2x = -12</em></h3><h3><em>x = -12/2</em></h3><h3><em>x = -6 </em></h3><h3><em>12) x+52 + 67+x + 75 = 180 ( angle sum property )</em></h3><h3><em>2x + 194 = 180 </em></h3><h3><em>2x = 180 - 194 </em></h3><h3><em>2x = -14</em></h3><h3><em>x = -14/2 </em></h3><h3><em>x = -7 </em></h3><h2><em>HOPE IT HELPS !!!</em></h2>
5 0
3 years ago
Read 2 more answers
What is cardiorespiratory endurance?
aev [14]
A. the ability of your heart and lungs to work during prolonged exercise. 

Hope this helps!:)
7 0
3 years ago
Read 2 more answers
Jordan and Erica both walk to school. 3/4 of the distance that
lys-0071 [83]

The person whose walk is longer is Erica.

Erica's walk is 8/9 times longer than Erica's walk.

<h3>Whose walks the longer distance?</h3>

In order to determine who walked the longer distance, we would convert the fractions to percentages.

3/4 becomes 75%

2/3 becomes 66.7%

Erica's percentage is smaller, thus, she walks a longer distance.

Jordan's walk is 8/9 times longer

(2/3 ÷3/4) (2/3 x 4/3 = 8/9)

To learn more about percentages, please check: brainly.com/question/25764815

8 0
2 years ago
Suppose that vector v lies in quadrant II, quadrant III, or quadrant IV. How can you use trigonometric ratios to calculate the d
Annette [7]
I just had a test on vectors so I feel your pain! Explained in the picture above. Hope it helps C:
Edit: in picture I say tantheta = x/y sorry I meant y/x

3 0
3 years ago
Read 2 more answers
Use the quadratic formula to solve for x.
ryzh [129]

Answer:

The answer is

x =   \frac{ - 9 -  \sqrt{41} }{10}  \:  \:   \: ,  \:  \:  \:  \:  \:   \frac{ - 9 +  \sqrt{41} }{10}  \\

Step-by-step explanation:

5x² + 9x + 2 = 0

Using the quadratic formula that's

x =  \frac{ - b \pm \sqrt{ {b}^{2}  - 4ac} }{2a}  \\

From the question

a = 5 , b = 9 , c = 2

We have

x =   \frac{ - 9 \pm \sqrt{ {9}^{2} - 4(5)(2) } }{2(5)}  \\  =  \frac{ - 9 \pm \sqrt{81 -40 } }{10}  \\  =  \frac{ - 9 \pm \sqrt{41} }{10}   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:

We have the final answer as

x =   \frac{ - 9 -  \sqrt{41} }{10}  \:  \:   \: ,  \:  \:  \:  \:  \:   \frac{ - 9 +  \sqrt{41} }{10}  \\

Hope this helps you

8 0
3 years ago
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