Question

The sum of two numbers is 167. The second number is 29 less than three times the first number. Fine the numbers. The two required numbers are:

Answer 1

Answer:

$\Huge \boxed{\mathrm{49 \ and \ 118}}$

Step-by-step explanation:

Let the first number be $x$

Let the second number be $y$

$x+y=167$

$y=3x-29$

Applying substitution method.

$x+3x-29=167$

Combining like terms.

$4x-29=167$

Adding 29 to both sides.

$4x=196$

Dividing both sides by 4.

$x=49$

Substituting x = 49 for the second equation.

$y=3(49)-29$

Multiplying the numbers.

$y=147-29$

Subtracting.

$y=118$

The two required numbers are 49 and 118.

Answer 2

Answer:

49 and 118

Step-by-step explanation:

Let the two numbers be x and y

x+y = 167

y = 3x-29

Substitute into the first equation

x+ 3x-29 = 167

Combine like terms

4x - 29 = 167

add 29 to each side

4x = 167+29

4x = 196

Divide by 4

4x/4 = 196/4

x = 49

x+y = 167

49+y = 167

y = 167-49

y =118