Consider the following sets of sample data: A: $29,400, $30,900, $21,000, $33,200, $21,300, $24,600, $29,500, $22,500, $35,200,
Lana71 [14]
Answer:
CV for A = 21.8%
CV for B = 15.5%
Step-by-step explanation:
The formula for coefficient of variation is:
CV = Standard Deviation / Mean
So,
For A:
Mean = Sum/No. of items
= 391300/14
=$27950
and
SD = $6085.31
CV for A = 6085.31/27950 * 100
=21.77%
Rounding off to one decimal
CV for A = 21.8%
For B:
Mean = Sum/No. of items
= 43.58/11
=3.96
and
SD = 0.615
CV for B = 0.615/3.96 * 100
=15.53%
=15.5% ..
Answer:
Step-by-step explanation:
A circle is inscribed in an equilateral triangle PQR with centre O. If angle OQR = 30°, what is the perimeter of the triangle?
This is a circle inscribed in an equilateral triangle with side s.
If you are asking for the perimeter of PQR, it is 3s.
If you are asking for the perimeter of OQR, it is (3+23–√3)s
Since OR and SR are the hypotenuses of right triangles with adjacent side equal to ½ s, their length is ½s / cos 30° = (√3) /3.
(3/3)s + ((√3) /3)s + ((√3) /3)s = ((3 + 2√3)/3)s ≈ 2.1547s
Hope it helps
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Answer:
4
Step-by-step explanation:
Class width is said to be the difference between the upper class limit and the lower class limit consecutive classes of a grouped data. To calculate class width, this formula can be used:
CW = UCL - LCL
Where,
CW= Class width
UCL= Upper class limit
LCL= Lower class limit
From the table above:
For class 1, CW = 64 - 60 = 4
For class 2, CW = 69 - 65 = 4
For class 3, CW = 74 - 70 = 4
For class 4, CW = 79 - 75 = 4
For class 5, CW = 84 - 80 = 4
Therefore, the class width of the grouped data = 4
