Answer:
C(t) = $28,000(0.811)^t (Answer A)
Step-by-step explanation:
The value of the car is decreasing. Thus, by the end of the first year of ownership, the car will have the value $28,000(1 -0.189)^1, where the "-0.189" represents DECAY instead of GROWTH.
Please use " ^ " to indicate exponentiation.
Then the desired formula is C(t) = $28,000(0.811)^t (Answer A)
You work out unit rates by making the denominator 1
Answer:
The correct option is;
B. This equation is not considered to be a quadratic equation because it is not in the form a·x² + b·x + c = 0
Step-by-step explanation:
A. The given equation, x² - c = 0, can be presented in the form of the difference of two squares as follows;
(x + √c)·(x - √c) = 0
B. The equation x² - c = 0, is a quadratic equation because it is a polynomial equation of degree 2
C. The equation x² - c = 0 can always be factored as (x + √c)·(x - √c) = 0
D. Where c > 0, the equation x² - c = 0 can by the square root property as follows;
x² - c = 0
x² = c
x = √c
Answer:
Option (2)
Step-by-step explanation:
In this question we have to find the multiplication of the two expressions.
(2p + q)(-3q - 6p + 1)
= 2p(-3q - 6p + 1) + q(-3q - 6p + 1) [By distributive property]
= -6pq - 12p²+ 2p - 3q² - 6pq + q
= -12p² - (6pq + 6pq) - 3q² + 2p + q
= -12p² - 12pq + 2p - 3q² + q
Therefore, Option (2) will be the correct option.
Answer:
Step-by-step explanation:
To find the time at which both balls are at the same height, set the equations equal to each other then solve for t.
h = -16t^2 + 56t
h = -16t^2 + 156t - 248
-16t^2 + 56t = -16t^2 + 156t - 248
You can cancel out the -16t^2's to get
56t = 156t - 248
=> 0 = 100t - 248
=> 248 = 100t
=> 2.48 = t
Using this time value, plug into either equation to find the height.
h = 16(2.48)^2 + 56(2.48)
Final answer:
h = 40.4736
