Answer:
The fraction of Sr-90 left after 73 years is 0.1726
Explanation:
Initial mass of the isotope =
Time taken by the sample, t =
Formula used :
where,
= initial mass of isotope
N = mass of the parent isotope left after the time, (t)
= half life of the isotope
= rate constant
We have:
t = (2018 - 1945 )years = 73 years
So, on substituting the values:
Now put all the given values in this formula, we get
The fraction of Sr-90 left after 73 years = 0.1726
Answer:
sorry i dont understand
Explanation:
i am russian but i do school in english so i dont know what some of these elements are exept for water
Answer:
The molar mass of is 96.8 g/mol
Explanation:
The given molecular formula -
Individual molar masses of each element in the compound is as follows.
Molar mass of nitrogen - 14.01 g/mol
Molar mass of of hydrogen = 1.008g/mol
Molar mass of carbon = 12.01 g/mol
Molar mass of oxygen =16.00 g/mol
Molar mass of is
Therefore,The molar mass of is 96.8 g/mol
You're oxidising agent will be reduced. In the molecule MnO4-, Mn has and oxidation number of +9 and in MnO2 it is +4, therefore its oxidation number has reduced, therefore Mn is reduced, therefore it is the oxidant/oxidising agent.