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klemol [59]
3 years ago
9

Draw the structural formula for 3-ethyl-3-methyl-1-pentyne. Click the "draw structure" button to launch the drawing utility.

Chemistry
1 answer:
Dima020 [189]3 years ago
6 0

Answer:

See attached picture.

Explanation:

Hello,

In this case, for the given name, you can verify the structure on the attached picture, wherein you can see verify the presence of both the ethyl and methyl radicals at the third carbon as well as the triple bond at the first carbon.

Best regards.

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N2+3H2 → 2NH3
s2008m [1.1K]

Explanation:

N2 (g) + H2 (g) gives out NH3 (g)

Now balance it. You have two reactants with compositions involving a single element, which makes it very easy to keep track of how much is on each side. I would balance the nitrogens, and then the hydrogens.

Now balance it. You have two reactants with compositions involving a single element, which makes it very easy to keep track of how much is on each side. I would balance the nitrogens, and then the hydrogens.(If you balance the hydrogen reactant with a whole number first, I can guarantee you that you will have to give NH3 a new stoichiometric coefficient.)

N2 (g) + 3H2 (g) gives out 2NH3 (g)

The stoichiometric coefficients tell you that if we can somehow treat every component in the reaction as the same (like on a per-mol basis, hinthint), then one "[molar] equivalent" of nitrogen yields two [molar] equivalents of ammonia.

Luckily, one mol of anything is equal in quantity to one mol of anything else because the comparison is made in the units of mols.

So what do we do? Convert to

mols (remember the hint?).

28g N2 × 1 mol N2/ 2 × 14.007) g N2

= 0.9995 mol N2

At this point you don't even need to calculate the number of mols of H2 . Why? Because H2 is about 2 g/mol, which means we have over 10 mols of H2. We have 1 mol N2, and we need three times as many mols of H2 as we have

N2.

After doing the actual calculation you should realize that we have about 4 times as much H2 as we need. Therefore the limiting reagent is clearly N2.

Thus, we should yield 2×0.9995=1.9990 mols of NH3 (refer back to the reaction). So this is the second and last calculation we need to do:

1.9990 mol NH3 × 17.0307 g NH3/ 1 mol NH3

= 34.0444 g NH3

Hope it helpz~

4 0
2 years ago
What happens in a reduction half-reaction?
Marta_Voda [28]
The answer is elements gain electrons. Oxidation reduction is elements lose electrons. And oxygen is added/lost can be a type of oxidation/reduction reaction.
3 0
3 years ago
Read 2 more answers
What occurs when a magnesium atom becomes a magnesium ion?
IgorLugansk [536]
The atom<span> then has more protons than electrons and so it will be positively charged, a positive </span>ion<span>. Example: A </span>magnesium atom<span> may lose two electrons and </span>become<span> a Mg2+ </span>ion<span>. Non-metal </span>atoms<span> may gain electrons and </span>become<span> negatively charged. ... (It loses two electrons.)</span>
6 0
3 years ago
How does Arizona's climate relate to the air and ocean currents?
harkovskaia [24]

Answer: In Arizona, climate change is already making deadly heat waves, droughts and wildfires across the state worse. These impacts have real costs on Arizonans' health and economy, including heat-related deaths, higher electricity bills, crop losses and more.

Explanation:

https://www.edf.org/climate/costofinaction- this is where I gathered this info.  Not mine.  But I hope it helps!

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Which type of bond is present in hydrogen sulfide (H2S)? The table of electronegativities is given.
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