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UNO [17]
3 years ago
11

What pressure is exerted on the bottom of a 0.500-m-wide by 0.900-m-long gas tank that can hold 50.0 kg of gasoline by the weigh

t of the gasoline in it when it is full?
Chemistry
1 answer:
Natasha_Volkova [10]3 years ago
8 0

Answer:

1088.89 Pa

Explanation:

According to the Newton's second law of motion:-

Force=Mass\times Acceleration

Mass = 50.0 kg

Acceleration = g = 9.81 m/s²

So,  

Force=50.0\times 9.8\ kgm/s^2

Force = 490 N

Area of the base = length\times breath = 0.500\times 0.900 m² = 0.45 m²

<u>Pressure = Force/Area = \frac{490\ N}{0.45\ m^2} = 1088.89 Pa</u>

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Answer is : It is a good thermal and electrical conductor. -The main point to be noted is that aluminium is a highly reactive element and still it is used for making cooking utensils. The reason is that aluminium has a very high affinity for oxygen. So, it reacts with oxygen and forms a layer of aluminium oxide on its surface.

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Match the alkane names and structures.<br> -butane<br> -methane<br> -ethane<br> -propane
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Answer:

Explanation:

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3 years ago
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F a sample of butene (C4H8) that has a mass of 136.6 g is combusted in excess oxygen, what is the mass of CO2 that is produced?
alukav5142 [94]

The balanced chemical reaction will be:

C4H8 + 6 O2 --> 4 CO2 + 4 H2O

We are given the amount of butene being combusted. This will be our starting point.

136.6 g C4H8 (1 mol  C4H8/ 56.11 g C4H8) (4 mol CO2/1 mol <span>C4H8</span>) ( 44.01 g CO2/ 1 mol CO2) = 428.6 g CO2
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3 years ago
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What is the theoretical yield of aluminum oxide if 3.00 mol of aluminum metal is exposed to 2.55 mol of oxygen?
lisabon 2012 [21]

Theoretical yield of Al₂O₃: 1.50 mol.

<h3>Explanation</h3>

2 \; \text{Al} + \dfrac{3}{2} \; \text{O}_2 \to {\bf 1} \; \text{Al}_2\text{O}_3;

4 \; \text{Al} + 3 \; \text{O}_2 \to 2 \; \text{Al}_2\text{O}_3 \; \textit{Balanced}.

How many moles of aluminum oxide formula units will be produced <em>if</em> aluminum is the limiting reactant?

Aluminum reacts to aluminum oxide at a two-to-one ratio.

3.00 \times \dfrac{1}{2} = 1.50 \; \text{mol}.

As a result, 3.00 moles of aluminum will give rise to 1.50 moles of aluminum oxide.

How many moles of aluminum oxide formula units will be produced <em>if</em> oxygen is the limiting reactant?

Oxygen reacts to produce aluminum oxide at a three-to-two ratio.

2.55 \times \dfrac{2}{3} = 1.70 \; \text{mol}

As a result, 2.55 moles of oxygen will give rise to 1.70 moles of aluminum oxide.

How many moles of aluminum oxide formula units will be produced?

Aluminum is the limiting reactant. Only 1.50 moles of aluminum oxide formula units will be produced. 1.70 moles isn't feasible since aluminum would run out by the time 1.50 moles was produced.

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