Both parents' genotypes are Bb (brown blue)
the punnet square would be
BB(kid one) Bb(kid two) Bb(kid three) bb(kid four)
kid one will be homozygous for brown eyes. kid two and three will be heterozygous for brown eyes. kid four will be homozygous for blue eyes
in other words, 75% will have brown eyes. 25% will have blue eyes
Plasma membrane, Ribosomes, cytoplasm, and DNA.
The most important reason they are considered non living is because they cannot live and reproduce without the help of a host cell.
