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erastovalidia [21]
3 years ago
9

20 POINTS - MONOHYBRID CROSS

Biology
2 answers:
kvv77 [185]3 years ago
8 0
To make it easier, 75% would have blue eyes
Stella [2.4K]3 years ago
7 0
Both parents' genotypes are Bb (brown blue)
the punnet square would be
BB(kid one) Bb(kid two) Bb(kid three) bb(kid four)
kid one will be homozygous for brown eyes. kid two and three will be heterozygous for brown eyes. kid four will be homozygous for blue eyes

in other words, 75% will have brown eyes. 25% will have blue eyes
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