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QveST [7]
3 years ago
15

PLZ HELP List all the possible numbers of pennies that Gigi could have in order to have her pennies into rectangular array with

more than one row or column and she has a remainder (in this case leftover pennies). Remember she must have between 10 and 30 pennies total.
Mathematics
1 answer:
viktelen [127]3 years ago
5 0

Answer:

If Gigi has between 10 and 30 pennies, all the possible combinations that form a rectangle with more than 1 column and row are:

  • 2 x 5 or 5 x 2 (10 pennies in total)
  • 2 x 6 or 6 x 2 (12 pennies in total)
  • 2 x 7 or 7 x 2 (14 pennies in total)
  • 2 x 8 or 8 x 2 (16 pennies in total)
  • 2 x 9 or 9 x 2 (18 pennies in total)
  • 2 x 10 or 10 x 2 (20 pennies in total)
  • 2 x 11 or 11 x 2 (22 pennies in total)
  • 2 x 12 or 12 x 2 (24 pennies in total)
  • 2 x 13 or 13 x 2 (26 pennies in total)
  • 2 x 14 or 14 x 2 (28 pennies in total)
  • 2 x 15 or 15 x 2 (30 pennies in total)
  • 3 x 4 or 4 x 3 (12 pennies in total)
  • 3 x 5 or 5 x 3 (15 pennies in total)
  • 3 x 6 or 6 x 3 (18 pennies in total)
  • 3 x 7 or 7 x 3 (21 pennies in total)
  • 3 x 8 or 8 x 3 (24 pennies in total)
  • 3 x 9 or 9 x 3 (27 pennies in total)
  • 3 x 10 or 10 x 3 (30 pennies in total)
  • 4 x 4 (16 pennies in total)
  • 4 x 5 or 5 x 4 (20 pennies in total)
  • 4 x 6 or 6 x 4 (24 pennies in total)
  • 4 x 7 or 7 x 4 (28 pennies in total)
  • 5 x 5 (25 pennies in total)
  • 5 x 6 or 6 x 5 (30 pennies in total)
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\large\boxed{ 14.875}

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Surveys indicate that two-thirds of all voters in Ward 5 plan on choosing Spike Jones for commissioner. If there are 500 voters
olya-2409 [2.1K]

<u>Answer:</u>

333 people of ward 5 are going to be voting for Spike Jones.

<u>Solution:</u>

We have been given that two-thirds of all voters in Ward 5 plan on choosing Spike Jones for commissioner.  

There are 500 voters in Ward 5.

Since 2/3 of all voters in Ward 5 are voting for Spike Jones the remaining 1/3 will not be voting for him.

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let d = # dimes

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if we solve the first equation for 'n' we get:  

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now we can substitute this in for 'n' in the second equation:

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