Answer:
4989600 ways
Step-by-step explanation:
From the question,
The word MATHEMATICS can be arranged in n!/(r₁!r₂!r₃!)
⇒ n!/(r₁!r₂!r₃!) ways
Where n = total number of letters, r₁ = number of times M appears r₂ = number of times A appears, r₃ = number of times T appears.
Given: n = 11, r₁ = 2, r₂ = 2, r₃ = 2
Substitute these value into the expression above
11!/(2!2!2!) = (39916800/8) ways
4989600 ways
Hence the number of ways MATHEMATICS can be arranged without duplicate is 4989600 ways
Answer:
Y = 6 I’m pretty sure if its not 6 it’s -6
Step-by-step explanation:
Answer:
Your answer is:
1) 6 ( 5 + 8 ) = 78
2) 5 ( 10 + 3 ) = 65
3) 9 ( 2 + 4 ) = 54
4) 7 ( 3 + 6 ) = 63
Step-by-step explanation:
Hope this helped : )
I believe it 9/20
hope that helped!!!
:)
if its not give the multiple answer choice if it has one!<span />
49 unit because and any subsequent words was ignored because we limit queries to 32 words.
