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Alex73 [517]
4 years ago
6

6+2+2/3+2/9+...+a6 evaluate

Mathematics
1 answer:
padilas [110]4 years ago
6 0

Answer:

8.987 (Approximate)

Step-by-step explanation:

We have to find the sum of a G.P. series up to sixth terms.

The first term of the series is 6 and common ratio is \frac{1}{3}.

So, the sum is  

6 + 2 + \frac{2}{3} + \frac{2}{9} + \frac{2}{27} + \frac{2}{81}

= 6 \times \frac{1 - (\frac{1}{3})^{6}}{1 - \frac{1}{3} }

= 8.987 (Approximate) (Answer)

We know the sum of a G.P.

a + ar + ar² + ar³ + ......... up to n terms = a\frac{1 - r^{n}}{1 - r}  

where -1 < r < 1.

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