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Ksju [112]
3 years ago
13

Kaylee is painting a design on the floor of a recreation room using equilateral triangles. She begins by painting the outline of

Triangle 1 measuring 50 inches on a side. Next, she paints the outline of Triangle 2 inside the first triangle. The side length of Triangle 2 is 80% of the length of Triangle 1. She continues painting triangles inside triangles using the 80% reduction factor. Which triangle will first have a side length of less than 29 inches?
Mathematics
2 answers:
KatRina [158]3 years ago
8 0
The correct answer for the given problem above would be the fourth triangle. So here is the given solution: Since Triangle 1 is already given with a measurement of 50 inches, and 80% of 50 inches if 40. Triangle 2 then is 40 inches. 80% of 40 is 32, so triangle 3 is 32 inches, and then 80% of 32 is 25.6 inches so triangle 4 is 25.6 inches. Therefore, the triangle that will first have a side length of less than 29 inches is triangle 4.
Archy [21]3 years ago
8 0

Answer:

A. Triangle 4

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Someone help me please :(
Aleksandr-060686 [28]

9514 1404 393

Answer:

  A.  ∠EAG and ∠BAC

Step-by-step explanation:

Vertical angles share a vertex and have opposite rays for sides.

Rays AE and AB are opposite; rays AG and AC are opposite. These are the only pairs of opposite rays in the figure, so the vertical angles must be constructed from one of the rays of the first pair and one of the rays of the second pair. ∠EAG and ∠BAC are a pair of vertical angles.

The other pair is ∠EAC and ∠BAG.

5 0
3 years ago
If , find the value of 2 square root of 17-x = 2x-10, find the value of x/4.
ira [324]
2 \sqrt{17-x} =2x-10\ \ \ \ \Rightarrow\ \ \ D:(17-x \geq 0\ \ \ and\ \ \ 2x-10 \geq 0)\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x \leq 17\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  \ \ x \geq 5\\\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ D=\\\\2 \sqrt{17-x} =2(x-5)\ /:2\\\\ \sqrt{17-x} =x-5\ \ \ \Rightarrow\ \ \ (\sqrt{17-x})^2 =(x-5)^2\\\\17-x=x^2-10x+25\\\\

x^2-9x+18=0\\\\ x^2-3x-6x+18=0\\\\x(x-3)-6(x-3)=0\\\\(x-3)(x-6)=0\ \ \ \ \Leftrightarrow\ \ \ (x-3=0\ \ \ \ or\ \ \ \ x-6=0)\\\\x=3\ \notin\ D\ \ \ \ \ \ \ \ \ \ \ x=6\ \in\ D\ \ \ \Rightarrow\ \ \  \frac{x}{4} = \frac{6}{4} =1.5\\\\Ans.\  \frac{x}{4} =1.5
7 0
3 years ago
Help with this problem^
Fittoniya [83]
This formula is the exposition of 8 and equals to 6 how u ask ? well if u 8 minus 2 u get 6 than add 6
6 0
3 years ago
Solve for the given variable (see pic)
4vir4ik [10]
27+a=32
a=32-27
a=5


Hope this helped you :)
7 0
3 years ago
Read 2 more answers
LONG WORD PROBLEM I KNOW! PLEASE ILL GIVE THANKS BRAINLIEST AND POINTS FOR THIS ANSWER! PLEASE!
11Alexandr11 [23.1K]
Answer:
5X + 8Y >= 300; intersection at (-20, 50)
Step-by-step explanation:
let t = work hours
0 < t < 30
X = time lawn mowing
Y = time babysitting.
X + Y < 30
5X + 8Y >= 300
We could solve...
X < 30 - Y
5(30 - Y) + 8Y >=300
150 - 5Y + 8Y >= 300
3Y >=150
Y >=50
then X < -20
intersection at (-20, 50)
5 0
3 years ago
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