(1 point) Consider the universal set U={1,2,3,4,5,6,7,8,9,10}, define the set A be the even numbers, the set B be the odd number
Sloan [31]
Answer:
a) AUC = {2,4,6,8,10}
b) BnC = {}
c) AnB = {}
d) B-C = B = {1,3,5,7,9}
Step-by-step explanation:
The set A is the even numbers, those that are divisible by two.
So A = {2,4,6,8,10}
B is the odd numbe.rs. An odd number is a number that is not divisible by two.
So B = {1,3,5,7,9}.
C = {4,5,6}, as the problem states
a) The union of sets is a set containing all elements that are in at least one of the sets. So the union of A and C is a set that contains all elements that are in at least one of A or C.
So AUC = {2,4,6,8,10}.
b) The intersection of two sets consists of all elements that in both sets. So, the intersection of B and C is the set that contains all elements that are in both B and C.
There are no elements that are in both B and C, so the intersection is an empty set
BnC = {}
c) Same explanation as b), there are no elements that are in both A and B, so another empty set.
AnB = {}
d) The difference of sets B and C consists of all elements that are in B and not in C. We already have in b) that BnC = {}, so:
B-C = B = {1,3,5,7,9}
Answer:
well bcs we cool so appreciated <3 periodTH lolz
Step-by-step explanation:
Answer:
Explaination:
Step-by-step explanation:
B: yes; 18^2 + 29^2=1165(equal sign with slash) 23^2
Answer:
$8882.9
Step-by-step explanation:
A=p(1+(r/n))^nt
Given:P=7000, r=(3÷100%)=0.03 , n=2, t=8
A = 7000(1+(.03/2))^(2×8)
A = 7000 (1+0.015)^16
A = 7000 × 1.015^16
A = $8882.9
