Question

Which statement is true about judy's method?

Answer 1

All of the above cause A is wrong 

Answer 2

A. Judy made a mistake between Steps 1 and 2
To factor $x^{2} - 16$, you have to factor it as $(x-2)(x+2)(x-4)$, not $(x-2)(x+8)$, because that will leave an extra 6x because of 8x - 2x.