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ser-zykov [4K]
3 years ago
9

I need to know how to do Solving Systems of Equations by Elimination

Mathematics
1 answer:
vredina [299]3 years ago
6 0
The point of elimination is to have one variable so example

3x + 2y = 4

7X + 3y = 5


1) Try to find a way to have one variable

7(3x + 2y = 4) ----> 21x + 14y = 28

-3(7x+ 3y = 5) -----> -21x -9y = -15


2) add

0 + 5y = 13

3) solve for the last variable

5y = 13
y = 13/5 = 2 3/5 = 2.8

4) Subsitute the variable to get the other one

3x + 2(2.8) = 4

3x + 5.6 = 4

3x = -1.6

x = 0.533333333 (continue)

The intersection would be 0.53 with a line above the 3 and 2.8. (0.5333 , 2.8)

Hope you understand!!
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Victor plants 56 seeds in some flower pots if he puts 7 seeds in each pot how many flower pots does he have
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Answer:

8

Step-by-step explanation:

The total seeds Victor plants in the flower pots=56

He puts 7 seeds in each pot.

So to find the number of pots;

You need to divide the total seeds(56) by the seeds put in each(7)

So it's going to be;

56÷7

=8

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How many triangles can be made with the angle 70°, 70°, and 70°
seraphim [82]
Hey there!
Your answer is 0.
All the angles of a triangle must add up to 180 degrees.
However, the sum of these angles is not equal to 180 degrees.
70 + 70 + 70 = 210
210 is not equal to 180.
Hence, no triangles can be made using the angles 70, 70, and 70.
Hope this helps!
7 0
3 years ago
In Exercises 10 and 11, points B and D are points of tangency. Find the value(s) of x.<br>​
Lemur [1.5K]

In both cases,

AB^2=AD^2

(as a consequence of the interesecting secant-tangent theorem)

So we have

10.

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20x^2-92x-40=0

5x^2-23x-10=0

(5x+2)(x-5)=0\implies\boxed{x=5}

(omit the negative solution because that would make at least one of AB or AD have negative length)

11.

(4x^2-18x-10)^2=(x^2+x+4)^2

16x^4-144x^3+244x^2+360x+100=x^4+2x^3+9x^2+8x+16

15x^4-146x^3+235x^2+352x+84=0

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(again, omit the solutions that would give a negative length for either AB or AD)

7 0
3 years ago
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