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maria [59]
2 years ago
6

Which ordered pair is a solution of the equation?

Mathematics
2 answers:
seraphim [82]2 years ago
8 0

Answer:

B.- Only (-3,5)

Step-by-step explanation:

In an ordered pair the first coordinate is the x coordinate, and the second coordinate corresponds to the y coordinate.

Then we must substitute the given value of x in the equation and verify that we get in return the defined value for y.

the options are

  • (-2,4)

in this one x = -2, and y=4, so let's confirm:

y=-3x-4\\y=-3(-2)-4\\y=-6-4\\y=2this is not a solution since the y values are not the same.

  • (-3,5)

in this one x= -3 and y=5, let's also confirm:

y=-3(-3)-4\\y=9-4\\y=5in this one the values for y are equal, this is a solution for the equation.

frozen [14]2 years ago
3 0
It’s B because 5 = -3(-3) - 4
5=9-4
Just plug in the numbers and see what works
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A television game has 6 shows doors, of which the contests must pick 2. behind two of the doors are expensive cars, and behind t
Katyanochek1 [597]
The answer to this question:
One car probability 82/120
No car probability = 24/120
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I will focus answering the 3 doors probability since the 2nd door problem is solved in the previous problem. (brainly.com/question/5761449)

No car condition
1. 1st door consolation, 2nd door consolation=, 3rd door consolation= 4/6 * 3/5 * 2/4= 24/120
This was also can be found by: (4!/1!)/ (6!/3!) = 24/120

(At least one car probability)  is the opposite of (no car probability) In this case, the easier way is 
100% - (no car probability) = 120/120 - 24/120= 96/120

One car probability is (At least one car probability) - (2 car probability). It will be easier to count the 2 car probability and subtract the (At least one car probability) 
Two car condition:
1. 1st door car, 2nd door car, 3rd door consolation = 2/6 * 1/5 * 4/4 =8/ 120
2.1st door car, 2nd door consolation, 3rd door car =2/6 * 4/5 * 1/4 = 8/120
3. 1st door consolation, 2nd door car, 3rd door car= 4/6 * 2/5 * 1/4= 8/120
The total probability will be 8/120+ 8/120 + /120= 24/120
This was also can be found by: (2!) (4!/2!)/ (6!/3!) = 24/120

One car probability =  (At least one car probability) - (2 car probability)= 96/120-24/120= 82/120
3 0
3 years ago
At the end of a snow storm, Audrey saw there was a lot of snow on her front lawn.
Montano1993 [528]

An equation that represents the depth of snow on Audrey's lawn, in inches, t hours after the snow stopped falling is S = 10 - 2t

In this question, there was a depth of 10 inches of snow on the lawn when the storm ended and then it started a melting at a rate of 2 inches per hour.

We need to write an equation for S in terms of t, snow representing the depth of snow on Audrey's lawn, in inches, t hours after the snow stopped falling.

So, the equation would be,

S = 10 - 2t

Therefore,  an equation that represents the depth of snow on Audrey's lawn, in inches, t hours after the snow stopped falling is S = 10 - 2t

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3 0
1 year ago
Please help I’ll mark you as brainliest if correct!
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Increases by +2
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6 0
2 years ago
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Peggi put some hairbows in 6 party bags. Her sister Tori put 2 more
irga5000 [103]

Answer:

Peggi put a total of 18 hair bows in the bag

Step-by-step explanation: There at six bags with an unknown amount of hairbows in each bag. You add 2 to each bag and you will end up getting 12 hairbows from her sister because 6x2=12. then you subtract the total (30) from her sister Toris amount (30-12) this equals 18.

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3 years ago
In a sheet metal operation, three identical notches and four identical bends are required. If the operations can be done in any
goldfiish [28.3K]

Answer:

<h2>There are 5040 different possible sequences.</h2>

Step-by-step explanation:

Three identical notches and four identical bends are required in the sheet metal operation.

In total 7 things are required in the metal operation.

We can think it as we need to put the 3 notches and 4 bends in 7 places.

First, lets put the 3 notches in 3 places.

In order to do so, we need to choose 3 places from the 7 places.

We can choose 3 places in \frac{7!}{3!\times4!} = \frac{5\times6\times7}{6} = 35 ways.

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Thus, in total 35\times24\times6 = 5040 different possible sequences.

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