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4 years ago

Help Please

Physics

2 answers:

maria [59]4 years ago

7 0

Answer:

4.Outside the nucleus

Explanation:

The atoms have three subatomic particles: neutrons, protons and electrons.

Electrons in an atom are outside the nucleus, in a region that surrouns the nucleus. If electrons are lost, they are lost from outside the nucleus.

Inside the nucleus are only neutrons and protons, not electrons.

OleMash [197]4 years ago

6 0

They were lost from the nucleus

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A(n) ____ follows a curved path in space around Earth. No options.. I'm confused..

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It's a projectile near the earth under the influence of gravity only.

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4 years ago

While you are looking at the image of your feet in a plane mirror, you see a scratch in the glass. What is the approximate heigh

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Answer:

1.75 / 2 = 0.875 m

Explanation:

Provided the mirror is vertical and you are standing upright.

It could be most any altitude if the mirror is allowed any orientation.

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3 years ago

The exit nozzle in a jet engine receives air at 1200 K, 150 kPa with negligible kinetic energy. The exit pressure is 80 kPa, and

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Complete question:

The exit nozzle in a jet engine receives air at 1200 K, 150 kPa with negligible kinetic energy. The exit pressure is 80 kPa, and the process is reversible and adiabatic. Use constant specific heat at 300 K to find the exit velocity.

Answer:

The exit velocity is 629.41 m/s

Explanation:

Given;

initial temperature, T₁ = 1200K

initial pressure, P₁ = 150 kPa

final pressure, P₂ = 80 kPa

specific heat at 300 K, Cp = 1004 J/kgK

k = 1.4

Calculate final temperature;

$T_2 = T_1(\frac{P_2}{P_1})^{\frac{k-1 }{k}$

k = 1.4

$T_2 = T_1(\frac{P_2}{P_1})^{\frac{k-1 }{k}}\\\\T_2 = 1200(\frac{80}{150})^{\frac{1.4-1 }{1.4}}\\\\T_2 = 1002.714K$

Work done is given as;

$W = \frac{1}{2} *m*(v_i^2 - v_e^2)$

inlet velocity is negligible;

$v_e = \sqrt{\frac{2W}{m} } = \sqrt{2*C_p(T_1-T_2)} \\\\v_e = \sqrt{2*1004(1200-1002.714)}\\\\v_e = \sqrt{396150.288} \\\\v_e = 629.41 \ m/s$

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6 0

3 years ago

Superman takes 8 seconds to stop a runway train over a distance of 58 m using a power of

elena-14-01-66 [18.8K]

Answer:

Workdone = 600 Kilojoules

Explanation:

Given the following data:

Time = 8 seconds

Power = 75,000 Watts

Distance = 58 m

To find the work done;

Power can be defined as the energy required to do work per unit time.

Mathematically, it is given by the formula;

$Power = \frac {Energy}{time}$

Thus, work done is given by the formula;

Workdone = power * time

Workdone = 75000 * 8

Workdone = 600,000 = 600 KJ

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3 years ago

Suppose that a 1000 kg car is traveling at 25 m/s (aprox 55mph). Its brakes can apply a force of 5000N. What is the minimum dist

Brrunno [24]

Assuming the the car is travelling to the right (→):

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$= \frac{-5000}{1000}$

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The information we know:

$u = 25 \ ms^{-1}$

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Using one of the equations of motion:

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$= 62.5\ m$

8 0

3 years ago

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