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yaroslaw [1]
2 years ago
9

Calculate the torques about pivot P provided by the forces shown in the Figure 3, if L = 4.5 m

Physics
1 answer:
g100num [7]2 years ago
6 0

The definition of torque of a force we can find the total torque on the bar is

           τ = 246.2 N m

The torque of a force is defined by the relation

         τ = F x r

where the bold letters indicate vectors, τ is the torque, f the force, and r the distance from the pivot point.

We can calculate the magnitude of this expression

       τ = F r sin θ

where in the angle between the forces and the candidate

In this case, we have five forces

  • the force at point P does not create torque since its distance is zero.
  • The force applied to the end of the bar, the angle is zero and the sine value zero.

The other forces create a torque:

F₁ =   80 N, the distance is x₁ = 0.5L,  θ₁ = 37º

F₂ = -60 N, the distance is x₂ = 0.5L, angle θ = 90º

F₃ =  70 N the distance is x₃ = L, angles θ = 30º

with respect to the vertical, this angle with respect to the horizontal is

         θ’ = θ + 90

         θ‘ = 30+ 90

         θ₃' = 120º

substitute

         τ = F₁ x₁ sin θ₁ + F₂ x₂ sin θ₂ + F₃ x₃ sin  θ₃'

let's calculate

          τ = 80 0.5L sin 37 - 60 0.5L sin 90 + 70 L sin 120

          τ = 54.7L

indicate that the length of the bar is L + 4.5 m

           τ = 54.7  4.5

           τ = 246.2 Nm

Using the defined torque we can find the total torque on the bar is

           τ = 246.2 N m

Learn more about torque here:

brainly.com/question/6855614

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Answer:

655.82m

Explanation:

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One leg of the triangle will be the 308m

and the second leg of the triangle will be the 579m.

If we call the displacement x, by the pythagorean theorem:

x=\sqrt{308^2+579^2}

x=\sqrt{94,864+335,241}

x=\sqrt430,105}

x=655.82m

The displacement is 655.82m

3 0
3 years ago
In an experiment, one of the forces exerted on a proton is F⃗ =−αx2i^, where α=12N/m2. What is the potential-energy function for
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Answer:

The potential energy is -4x^3

Explanation:

Given that,

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Give an example of the of conservation of momentum
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Use the component form of newton's second law to write an expression for the x component of the net force, σfx
nordsb [41]

Draw a free body diagram to show which forces act in the x and y directions. The x component equation is σfx = 0. The σfx being all the forces acting in the x direction.
8 0
3 years ago
100 POINTS FOR CORRECT ANSWER/EXPLANATION
Shalnov [3]

Answer:

6 N

Explanation:

Let's start with the small block m on top.  There are four forces:

Weight force mg pulling down, normal force N₁ pushing up, tension force T pulling right, and friction force N₁μ pushing left (opposing the direction of motion).

Now let's look at the large block M on bottom.  There are seven forces:

Normal force N₁ pushing down (opposite and equal from block m),

Friction force N₁μ pushing right (opposite and equal from block m),

Weight force Mg pulling down,

Tension force T pulling right,

Applied force F pulling left,

Normal force N₂ pushing up,

and friction force N₂μ pushing right (opposing the direction of motion).

So you've correctly identified the free body diagrams.

Now apply Newton's second law.  Sum of forces in the y direction for block m:

∑F = ma

N₁ − mg = 0

N₁ = mg

Sum of forces in the x direction:

∑F = ma

T − N₁μ = 0

T = N₁μ

T = mgμ

Sum of forces in the y direction for block M:

∑F = ma

-N₁ − Mg + N₂ = 0

N₂ = N₁ + Mg

N₂ = mg + Mg

Sum of forces in the x direction:

∑F = ma

N₁μ + T − F + N₂μ = 0

F = N₁μ + T + N₂μ

F = mgμ + mgμ + (mg + Mg)μ

F = gμ(3m + M)

Since M = 2m:

F = 5gμm

Plug in values:

F = 5 (10 m/s²) (0.400) (0.300 kg)

F = 6 N

8 0
3 years ago
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