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yaroslaw [1]
3 years ago
9

Calculate the torques about pivot P provided by the forces shown in the Figure 3, if L = 4.5 m

Physics
1 answer:
g100num [7]3 years ago
6 0

The definition of torque of a force we can find the total torque on the bar is

           τ = 246.2 N m

The torque of a force is defined by the relation

         τ = F x r

where the bold letters indicate vectors, τ is the torque, f the force, and r the distance from the pivot point.

We can calculate the magnitude of this expression

       τ = F r sin θ

where in the angle between the forces and the candidate

In this case, we have five forces

  • the force at point P does not create torque since its distance is zero.
  • The force applied to the end of the bar, the angle is zero and the sine value zero.

The other forces create a torque:

F₁ =   80 N, the distance is x₁ = 0.5L,  θ₁ = 37º

F₂ = -60 N, the distance is x₂ = 0.5L, angle θ = 90º

F₃ =  70 N the distance is x₃ = L, angles θ = 30º

with respect to the vertical, this angle with respect to the horizontal is

         θ’ = θ + 90

         θ‘ = 30+ 90

         θ₃' = 120º

substitute

         τ = F₁ x₁ sin θ₁ + F₂ x₂ sin θ₂ + F₃ x₃ sin  θ₃'

let's calculate

          τ = 80 0.5L sin 37 - 60 0.5L sin 90 + 70 L sin 120

          τ = 54.7L

indicate that the length of the bar is L + 4.5 m

           τ = 54.7  4.5

           τ = 246.2 Nm

Using the defined torque we can find the total torque on the bar is

           τ = 246.2 N m

Learn more about torque here:

brainly.com/question/6855614

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Attract

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As the toy is initially electrically neutral, so as it is divided into two pieces, then according to the conservation of charge, the one piece having positive charge and the other piece having negative charge. As they are unlike charges so they attract each other.

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The current in the circuit is 12A

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3 years ago
An engine extracts 452.8kJ of heat from the burning of fuel each cycle, but rejects 266.7 kJ of heat (exhaust, friction,etc) dur
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Answer: The thermal efficiency of the engine is 41.09 %.

Explanation:

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Formula for thermal efficiency of engine is

\eta=1- \frac{Q_2}{Q_1}\times 100

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Putting in the values we get:

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4 years ago
A circular rod has a radius of curvature R = 9.09 cm and a uniformly distributed positive charge Q = 6.49 pC and subtends an ang
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Answer:

E = 1.19 N/C

Explanation:

Let's first determine the length of the arc which can be given as:

L= Rθ

where:

L = length of the arc

R = radius of curvature

θ = angle in radius

L = (9.09×10⁻²m)(2.59)

L = (0.0909)(2.59)

L = 0.235431 m

Then, the magnitude of electric field that Q produces at the center of curvature can be calculated by using the formula:

E= \frac{\lambda}{4 \pi E_oR}[sin\frac{\theta}{2}-sin(-\frac{\theta}{2})]

E= \frac{\lambda}{4 \pi E_oR}[sin\frac{\theta}{2}+sin(\frac{\theta}{2})]

E= \frac{2\lambda}{4 \pi E_oR}[sin\frac{\theta}{2}]

Since \lambda = \frac{Q}{L}

where;

L = length

Q = charge

λ =  density of the charge;

then substituting \frac{Q}{L} for λ, we have :

E= \frac{2(\frac{Q}{L})}{4 \pi E_oR}[sin\frac{\theta}{2}]

E= \frac{2Q[sin\frac{\theta}{2}]}{4 \pi E_oLR}

substituting our given parameter; we have:

E= \frac{2(6.26*10^{-12}C)[sin\frac{2.59rad}{2}]}{4 \pi (8.85*10^{-12}C^2/N.m^2)(0.235431)(0.0909)}

E = 1.1889 N/C

E = 1.19 N/C

∴ the magnitude of the electric field that Q produces at the center of curvature = 1.19 N/C

4 0
3 years ago
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